1. The percentage of people surveyed in East Harlem is 58.5%
2. The percentage of people surveyed in Upper East Side is 41.5%
From the question given above, the following data were obtained:
- People surveyed in East Harlem = 183
- People surveyed in Upper East Side = 130
- Total people surveyed = 313
1. Determination of the percentage of people surveyed in East Harlem.
- People surveyed in East Harlem = 183
- Total people surveyed = 313
- Percentage of East Harlem =?
Percentage of East Harlem = (people surveyed in East Harlem / Total) × 100
Percentage of East Harlem = (183/313) × 100
Percentage of East Harlem = 58.5%
2. Determination of the percentage of people surveyed in Upper East Side.
- Percentage of East Harlem = 58.5%
- Percentage of Upper East Side =?
Percentage of Upper East Side = (Total percentage) – (Percentage of East Harlem)
Percentage of Upper East Side = 100 – 58.5
Percentage of Upper East Side = 41.5%
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Temp in city for weeks 1-4 = Starting temp - (20 deg C / 4 wk) * wk#
Temp in City for weeks 1-4 = starting temp - 5 deg c/wk * wk#
This shows the temperature in the city for weeks 1 2 3 4 given the original temperature of the city and whichever week you want to know from the starting point....week 1 week 2 week 3 week 4 .....
Answer:
Answer: The statements are numbers 1, 3, 4
The non statements are 2, 5, 6
Step-by-step explanation:
Answer:
The tree is 12 feet tall
Step-by-step explanation:
Let a represent the length of where the bird was sitting to the oak tree
let b represent the height of the tree
let c represent the length at which the bird flew
by pythagoras theorem
c²=a²+b²
b²=c²-a²
subtitute in the values
