Question

Isoke is solving the quadratic equation by completing the square. 10x2 + 40x – 13 = 0        10x2 + 40x = 13         A(x2 + 4x) = 13 What is the value of A?

Answer 1

Answer:

 A = 10

Step-by-step explanation:

We have given that : A quadratic equation $10x^2+40x-13=0$

                                   another equation $A(x^2+4x)=13$

To find:  The value of A

Solution: Taking the quadratic equation  $10x^2+40x-13=0$

and try to reduce this equation in form of another equation

$10x^2+40x-13=0$ ⇒ $10(x^2+4x)=13$

Comparing with another equation $A(x^2+4x)=13$

we get that 10 takes the place of A

which implies value of A = 10

Answer 2

I hope this helps you




10x^2+40=13


10 (x^2+4)=13



A=10