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Rasek [7]
3 years ago
13

Which equation can pair with y=3x-2 to create a consistent and independent system?

Mathematics
2 answers:
pochemuha3 years ago
7 0

Answer:

x = 3y – 2

y = –3x – 2

3y – x = –2

Step-by-step explanation:

Ray Of Light [21]3 years ago
3 0

Answer: y=4

Step-by-step explanation:  First of all, we have to know what a consistent and independent system is.

Consistent and independent- If a consistent system has exactly one solution, and is independent, then it's consistent and independent

Let's graph the equation y=3x-2 first. The y intercept of the equation is -2 and the slope of the equation is 3. Lets plot the y intercept first, then use rise/run for the slope. We end off with the image of the first one I have attached to this answer.

Next, we can see if that we draw a straight arrow to one of the points in the equation, we will get a independent and consistent system. I picked y=4, but you can pick almost any point that lies within the line.

This will grant only one solution, which will give us what we need. So let's graph y=4. Finally, we have our consistent and independent system! I've attached another file to support my answer.

So the final answer to your question is y=4, the solution to the system is (2,4), as you can see by the last image.

<em><u> Give me feedback on my answer. Tell me if I'm lacking explanation about anything. Please help me, you can also help others by informing me what else I need to be specific on.</u></em>

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\bf (\stackrel{x_1}{4}~,~\stackrel{y_1}{-6})\qquad (\stackrel{x_2}{8}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{-4}-\stackrel{y1}{(-6)}}}{\underset{run} {\underset{x_2}{8}-\underset{x_1}{4}}}\implies \cfrac{-4+6}{4}\implies \cfrac{2}{4}\implies \cfrac{1}{2}

\bf \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-6)}=\stackrel{m}{\cfrac{1}{2}}(x-\stackrel{x_1}{4}) \\\\\\ y+6=\cfrac{1}{2}x-2\implies y=\cfrac{1}{2}x-8

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