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2 years ago

Find value of: cot^-1 (4) (inverse of cotangent). Give the reason of using cosine to evaluate.

Mathematics

1 answer:

solmaris [256]2 years ago

7 0

Cot x = cos x / sin x
or Cot x = 1/ tan x
Given:
Cot x = 4
Tan x = 1/4
x = 14.03 degrees

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The graphs below have the same shape. f(x) = x^2 what is the equation of the graph of g(x)?

Yakvenalex [24]

Answer:

Answer: OPTION B

Step-by-step explanation

By definition, the parent function is the simplest form of a function. In this case, you have the quadratic parent function

As you can see in the graph, the function g(x) is the obtained by shifting the parent function f(x) two units to the right, which is represented with:

Therefore, the equation of the function g(x) is:

6 0

3 years ago

Read 2 more answers

Alex has 520 yards of fencing to enclose a rectangular area.

Pavlova-9 [17]

Perimeter =2w+2L= 520.
We can solve this by understanding that the area is maximized by a square
Therefore L=w.

p=2w+2w=520=4w
w=130

Area

A=wL=130(130)= 16900 square yards

6 0

2 years ago

Read 2 more answers

Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimeters,

tiny-mole [99]

Answer:

Probability that the sample mean would be greater than 141.4 millimetres is 0.3594.

Step-by-step explanation:

We are given that Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 141 millimetres, and a standard deviation of 7.

A random sample of 39 steel bolts is selected.

Let $\bar X$ = sample mean diameter

The z score probability distribution for sample mean is given by;

Z = $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }$ ~ N(0,1)

where, $\mu$ = population mean diameter = 141 millimetres

$\sigma$ = standard deviation = 7 millimetres

n = sample of steel bolts = 39

Now, Percentage the sample mean would be greater than 141.4 millimetres is given by = P( $\bar X$ > 141.4 millimetres)

P( $\bar X$ > 141.4) = P( $\frac{ \bar X-\mu}{\frac{\sigma}{\sqrt{n} } } }$ > $\frac{141.4-141}{\frac{7}{\sqrt{39} } } }$ ) = P(Z > 0.36) = 1 - P(Z $\leq$ 0.36)

= 1 - 0.6406 = 0.3594

The above probability is calculated by looking at the value of x = 0.36 in the z table which has an area of 0.6406.

8 0

3 years ago

A bird (b) is spotted flying 900 feet from an observer. the observer (o) also spots the top of a tower (t) at a height of 200 fe

Svetach [21]

Angle of depression = 12.52°

The right angle triangle formed has a height of 200 ft and a base of 900 ft.

The opposite side of the triangle is 200 ft while the adjacent side of the triangle is 900 ft.

Using tangential ratio we can find the angle of depression. Therefore,

Let

x = angle of depression

tan x = opposite/adjacent

opposite = 200 ft

adjacent = 900 ft

tan x = 200/900

tan x = 2/9

x = tan⁻¹ 2/9

x = tan⁻¹ 0.222

x = 12.5166739144

x = 12.52°

To learn more about angle of depression from the given link

brainly.com/question/16772926

#SPJ4

3 0

1 year ago

Solve by factoring c^2=5c

muminat

Hey there!

c² = 5c

Subtract 5c from both sides:

c² - 5c = 5c - 5c

Simplify :

c² - 5c = 0

c = 5 , c = 0

6 0

2 years ago