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kobusy [5.1K]
3 years ago
9

ANSWER ASAP PLEASE AND THANK YOU

Mathematics
1 answer:
Romashka [77]3 years ago
7 0

Answer:

(C) $111.83

Step-by-step explanation:

If Sonya buys four pairs of shoes, each on a buy one get one 50% off, that means that we can find the value if she bought ONE deal of buy one get 50% off one, then multiply that by 2 (as if you do the deal, you are paying for two.)

The shoe costs $35, and if we have a 50% discount on it:

35\cdot0.5=17.5

So the cost of the shoe ON DISCOUNT is 17.50, however the first pair still stays the same.

So the cost of two pairs of shoes using the discount is 35+17.5 = 52.5

So four pairs cost 52.5\cdot2 = 105

However, there is a tax of 6.5%

So we can multiply 105 by 1.065 to get the cost after tax.

105\cdot1.065=111.825

This simplifies down to 111.83.

Hope this helped!

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A girl is half as old as her sister and is also two years younger than her brother. If the sum of the three children's ages is $
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13 and a half  5 and half and 16

5 0
3 years ago
In trapezoid ABCD, AC is a diagonal and ∠ABC≅∠ACD. Find AC if the lengths of the bases BC and AD are 12m and 27m respectively.
xz_007 [3.2K]

Answer:

Length of diagonal is 18 m

Step-by-step explanation:

Given in trapezoid ABCD. AC is a diagonal and ∠ABC≅∠ACD. The lengths of the bases BC and AD are 12m and 27m. We have to find the length of AC.

Let the length of diagonal be x m

In ΔABC and ΔACD

∠ABC=∠ACD      (∵Given)

∠ACB=∠CAD      (∵Alternate angles)

By AA similarity theorem, ΔABC~ΔACD

∴ their corresponding sides are proportional

\frac{x}{27}=\frac{12}{x}=\frac{AB}{CD}

Comparing first two, we get

⇒ \frac{x}{27}=\frac{12}{x}

⇒ x^2=27\times 12

⇒ x=\sqrt324=18

hence, the length of diagonal is 18 m



4 0
3 years ago
2 lines intersect. A line with points A, B, D intersects a line with points E, B, C at point B, forming 4 angles. In the diagram
solmaris [256]

Answer:

Its B and D

Step-by-step explanation:

7 0
3 years ago
Which graph shows the solution to the following system of linear inequalities?
rusak2 [61]

Answer:

See attached picture.

Step-by-step explanation:

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5 0
3 years ago
Show that 3x^2 -2x + 1 is always greater than 0.<br> ( This is an Additional Math Question )
Leviafan [203]

Answer:

3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3

(x-1/3)^2 is greater or equal to zero

3(x-1/3)^2 is greater or equal to zero

and 2/3 is greater than zero

So there sum is greater than zero

Proved

Step-by-step explanation:

3x^2 -2x + 1 =3(x^2-2/3x+1/3)

Consider x^2-2/3x+1/3

Remember that (a-b)^2 =a^2-2ab+b^2

x^2=a^2

a=x

-2/3x= -2*x*b

b=1/3

S0 (x-1/3)^2= x^2-2/3x+1/9

x^2-2/3x+1/3= x^2-2/3x+1/9+1/3-1/9= (x-1/3)^2+2/9

3x^2 -2x + 1 =3(x^2-2/3x+1/3)=3(x-1/3)^2+2/9*3= 3(x-1/3)^2+2/3

(x-1/3)^2 is greater or equal to zero

3(x-1/3)^2 is greater or equal to zero

and 2/3 is greater than zero

So there sum is greater than zero

Proved

6 0
3 years ago
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