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Ugo [173]
4 years ago
15

|x-1|+5=2 also this question

Mathematics
2 answers:
Marizza181 [45]4 years ago
6 0

Answer:

No solution

Step-by-step explanation:

There are no values of  x  that make the equation true.

Dmitrij [34]4 years ago
5 0

Answer: No solutions

==========================================

Explanation:

Start things off by subtracting 5 from both sides

|x-1|+5 = 2

|x-1|+5-5 = 2-5

|x-1| = -3

We cannot go any further after this point. The result of any absolute value is never negative. The absolute value represents distance from some number to 0. For example, saying |-7| = 7 means -7 is seven units away from 0 on a number line. Negative distance does not make sense.

So going back to |x-1| = -3 makes no sense as well. There are no numbers we can plug in for x to have |x-1| = -3 be true.

The equation |x-1| = -3 has no solutions, so the original equation doesn't have any solutions either.

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Find the slope and the y-intercept of the graph of y= 11 + 1.5x.
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Step-by-step explanation:

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Which of the following matrices is the solution matrix for the given system of equations? x + 5y = 11 x - y = 5
givi [52]
<h2>The required solution is x = 6 and y = 11 </h2>

Step-by-step explanation:

Given system of equations are

x+5y = 11 and x-y =5

A= \left[\begin{array}{cc}1&5\\1&-1\end{array}\right]                            X=\left[\begin{array}{c}x\\y\end{array}\right]

and          B= \left[\begin{array}{c}11\\5\end{array}\right]

∴AX=B

adj A = \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]

A= \left|\begin{array}{cc}1&5\\1&-1\end{array}\right|=-6

∴A^{-1} =\frac{adj A}{|A|}

So,A^{-1} =\frac{ \left[\begin{array}{cc}{-1}&{-5}\\{-1}&1\end{array}\right]}{-6}

A^{-1} ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]}

X =A^{-1}\times B

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c \c}  {{\frac{1}{6} }}&{\frac{5}{6}}\ \\  {{\frac{1}{6} }}&{\frac{-1}{6}} \end{array}\right]} \times \left[\begin{array}{c}11\\5\end{array}\right]

⇒\left[\begin{array}{c}x\\y\end{array}\right] ={ \left[\begin{array}{c}  {6}\\  {11} \end{array}\right]}

∴ x= 6 and y = 11

The required solution is x = 6 and y = 11

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