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Ugo [173]
3 years ago
15

|x-1|+5=2 also this question

Mathematics
2 answers:
Marizza181 [45]3 years ago
6 0

Answer:

No solution

Step-by-step explanation:

There are no values of  x  that make the equation true.

Dmitrij [34]3 years ago
5 0

Answer: No solutions

==========================================

Explanation:

Start things off by subtracting 5 from both sides

|x-1|+5 = 2

|x-1|+5-5 = 2-5

|x-1| = -3

We cannot go any further after this point. The result of any absolute value is never negative. The absolute value represents distance from some number to 0. For example, saying |-7| = 7 means -7 is seven units away from 0 on a number line. Negative distance does not make sense.

So going back to |x-1| = -3 makes no sense as well. There are no numbers we can plug in for x to have |x-1| = -3 be true.

The equation |x-1| = -3 has no solutions, so the original equation doesn't have any solutions either.

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3 years ago
Combine the like terms<br> 2g + 15 + 3g + g + g- 18
ZanzabumX [31]

Answer:

7g - 3

Step-by-step explanation:

2g + 15 + 3g + g + g - 18

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6 0
3 years ago
Evaluate 3^2 + (5 − 2) ⋅ 4 − 6 over 3.<br> 19<br> 16<br> 46<br> 24
Ludmilka [50]
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8 0
3 years ago
Can you help me i don’t know the answers
Advocard [28]
1)

An irrational number is a number that a) can't be written as a fraction of two whole numbers AND b) is an infinite decimal without any sort of pattern.

For the first answer choice, clearly \frac{1}{3} does not pass the first criterion so we look at the second choice.

Let's come back to \sqrt{2} and \pi.

\frac{2}{9} doesn't meet our first criterion, and let's skip \sqrt{3} for now.

It is often easier to disprove an irrational number than to prove one. There are a few famous irrationals to know (although there is an infinite number of irrationals). The most common are \sqrt{2},  \pi, e,  \sqrt{3}. For now, it's just helpful to know these and recognize them.

So we can check off \sqrt{2},  \pi and \sqrt{3}.

2) 

For this next question, we know that \sqrt{64} = 8. Clearly this isn't irrational. Likewise, \frac{1}{2} isn't irrational. \frac{16}{4} =  \frac{4}{4} = 1, which is rational, leaving only \frac{ \sqrt{20}}{5} =  \frac{2 \sqrt{5} }{5}. By process of elimination, this is the correct answer. Indeed, \sqrt{5} is an irrational number.

3) This notation means that we have 0.3636363636... and so on, to an infinite number of digits. It is called a repeating decimal.

But it can be written as a fraction because its pattern repeats, unlike for an irrational number.

Let's say x=0.36363636.... Would you agree that 100x=36.36363636...? (We choose to multiply by 100 because there are two decimals that repeat. For 1, choose 10, for 3 choose 1,000, and so on.)

Now, let's subtract x from 100x and solve.

100x=36.36363636\\-x \ \ \ \ \ \ \ -0.36363636\\99x=36\\\\x= \dfrac{36}{99}= \dfrac{4}{11}

Voila!
4 0
3 years ago
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Answer:

Step-by-step explanation:

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7 0
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