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IrinaK [193]
3 years ago
7

Help plz ASAP Find the value of x

Mathematics
1 answer:
SashulF [63]3 years ago
6 0

Answer:

122

Step-by-step explanation:

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Which equation has no solution?
polet [3.4K]

Answer:

number 3

Step-by-step explanation:

3 0
3 years ago
For integers a, b, and c, consider the linear Diophantine equation ax C by D c: Suppose integers x0 and y0 satisfy the equation;
Dmitrij [34]

Answer:

a.

x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )

b. x = -8 and y = 4

Step-by-step explanation:

This question is incomplete. I will type the complete question below before giving my solution.

For integers a, b, c, consider the linear Diophantine equation

ax+by=c

Suppose integers x0 and yo satisfy the equation; that is,

ax_0+by_0 = c

what other values

x = x_0+h and y=y_0+k

also satisfy ax + by = c? Formulate a conjecture that answers this question.

Devise some numerical examples to ground your exploration. For example, 6(-3) + 15*2 = 12.

Can you find other integers x and y such that 6x + 15y = 12?

How many other pairs of integers x and y can you find ?

Can you find infinitely many other solutions?

From the Extended Euclidean Algorithm, given any integers a and b, integers s and t can be found such that

as+bt=gcd(a,b)

the numbers s and t are not unique, but you only need one pair. Once s and t are found, since we are assuming that gcd(a,b) divides c, there exists an integer k such that gcd(a,b)k = c.

Multiplying as + bt = gcd(a,b) through by k you get

a(sk) + b(tk) = gcd(a,b)k = c

So this gives one solution, with x = sk and y = tk.

Now assuming that ax1 + by1 = c is a solution, and ax + by = c is some other solution. Taking the difference between the two, we get

a(x_1-x) + b(y_1-y)=0

Therefore,

a(x_1-x) = b(y-y_1)

This means that a divides b(y−y1), and therefore a/gcd(a,b) divides y−y1. Hence,

y = y_1+r(\frac{a}{gcd(a, b)})  for some integer r. Substituting into the equation

a(x_1-x)=rb(\frac{a}{gcd(a, b)} )\\gcd(a, b)*a(x_1-x)=rba

or

x = x_1-r(\frac{b}{gcd(a, b)} )

Thus if ax1 + by1 = c is any solution, then all solutions are of the form

x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )

In order to find all integer solutions to 6x + 15y = 12

we first use the Euclidean algorithm to find gcd(15,6); the parenthetical equation is how we will use this equality after we complete the computation.

15 = 6*2+3\\6=3*2+0

Therefore gcd(6,15) = 3. Since 3|12, the equation has integral solutions.

We then find a way of representing 3 as a linear combination of 6 and 15, using the Euclidean algorithm computation and the equalities, we have,

3 = 15-6*2

Because 4 multiplies 3 to give 12, we multiply by 4

12 = 15*4-6*8

So one solution is

x=-8 & y = 4

All other solutions will have the form

x=-8+\frac{15r}{3} = -8+5r\\y=4-\frac{6r}{3} =4-2r

where r ∈ Ζ

Hence by putting r values, we get many (x, y)

3 0
3 years ago
The median is often a better representative of the central value of a data set when the data set: source is bimodal. has a high
Lorico [155]
The median is a better representative of the central value of a data set when
the data set is highly skewed.

Note that
The median and average value only coincide when the distribution is perfectly normal.
Many outliers will also skew the distribution, and the median becomes a better representative.
8 0
3 years ago
Please help i need to move on:(
leonid [27]
I think it’s the second one
7 0
3 years ago
Read 2 more answers
A total of 729 students participate in a school pep rally event. If every 30 minutes, 2/3 of the students leave, after 2 hours,
trapecia [35]

There will be 9 students left at the prep rally after 2 hours.

After 30 minutes

  • Total Number of students = 729
  • 2/3 of 729 = 486
  • Number of students left = 729 - 486 = 243

After 1 hour:

  • 2/3 of 243 = 162
  • Number of students left = 243 - 162 = 81

After 1 hour 30 minutes :

  • 2/3 of 81 = 54
  • Number of students left = 81 - 54 = 27

After 2 hours :

  • 2/3 of 27 = 18
  • Number of students left = 27 - 18 = 9

Therefore, the Number of students left after 2 hours will be 9.

Learn more : brainly.com/question/18112348

5 0
2 years ago
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