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Cerrena [4.2K]
3 years ago
11

Idk what to do.... please help!

Mathematics
2 answers:
joja [24]3 years ago
4 0
The equation for the expression is M-4=A Because it says Amy is 4 years younger than Marty
ruslelena [56]3 years ago
3 0
Okay so Marty's age is m. That means we have NO IDEA how old he is. He could be 93 years old or 15 years old. We have no clue. Since he could be any number we will symbolize that number with m. Now it says that Amy is four years younger, this means we have to subtract 4 from any age that Marty is... 
this will give us: m-4
and that is your answer
You might be interested in
There are six poles on a side of a 1 km 200 m long straight road such that there is a pole at the starting and end points of the
Bingel [31]

Answer:

Distance is 200m between each pole

Step-by-step explanation:

First, convert the length of the road into meters

        1km= 1000m

        1000m +200m= 1200m

There are 6 poles on the side and they're equally spaced

Divide the length of the road by the number of poles to get the distance between the poles

        Distance between poles= Length of road/ Number of poles

        Distance between poles= 1200m/ 6 poles

       Distance between poles= 200m

       

5 0
3 years ago
There are n machines in a factory, each of them has defective rate of 0.01. Some maintainers are hired to help machines working.
frosja888 [35]

Answer:

a) 1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k!

b) 1 - ∑^(80x/d)_k=0 ((e^-λ) × λ^k) / k!

c) ∑²⁰ˣ_k=0 (3^k)/k! = 0.99e³

Step-by-step explanation:  

Given that;

if n ⇒ ∞

p ⇒ 0

⇒ np = Constant = λ,  we can apply poisson approximation

⇒ Here 'p' is small ( p=0.01)

⇒ if (n=large) we can approximate it as prior distribution

⇒ let the number of defective items be d

so p(d) = ((e^-λ) × λ) / d!

NOW

a)

Let there be x number of repairs, So they will repair 20x machines on time. So if the number of defective machine is greater than 20x they can not repair it on time.

λ[n0.01]

p[ d > 20x ] = 1 - [ d ≤ 20x ]

= 1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k!

b)

Similarly in this case if number of machines d > 80x/3;

Then it can not be repaired in time

p[ d > 80x/3 ]

1 - ∑^(80x/d)_k=0 ((e^-λ) × λ^k) / k!

c)

n = 300, lets do it for first case i.e;

p [ d > 20x } ≤ 0.01

1 - ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k! = 0.01

⇒ ∑²⁰ˣ_k=0 ((e^-λ) × λ^k) / k! = 0.99

⇒ ∑²⁰ˣ_k=0 (λ^k)/k! = 0.99e^λ

∑²⁰ˣ_k=0 (3^k)/k! = 0.99e³

8 0
2 years ago
Solve. <br> - 1/3b = 9<br><br> A. -3 <br> B. 3<br> C. - 27<br> D. 27
ruslelena [56]
-\dfrac{1}{3}b=9\ \ \ |multiply\ both\ sides\ by\ (-3)\\\\-3\cdot\left(-\dfrac{1}{3}b\right)=-3\cdot9\\\\\huge\boxed{b=-27}\leftarrow\boxed{C}
3 0
3 years ago
Read 2 more answers
Which of the following choices is an example of gathering evidence?
Anika [276]

Answer:

OA Taking Measurements

8 0
1 year ago
Can somebody help me with this question please ?
inysia [295]

Answer: No.

Step-by-step explanation: g should also be factored out. 10g(a - 3z).

4 0
2 years ago
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