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DENIUS [597]
4 years ago
8

Which of the following points is an equal distance (equidistant) from a(2, −2) and b(−4, 6)?

Mathematics
1 answer:
lesantik [10]4 years ago
6 0
The point equidistant from a(2, -2) and b(-4, 6)  is the midpoint

For (x₁, y₁) and (x₂, y₂) the midpoint is given by:

 ( (x₁ + x₂)/2 ,  (y₁ + y₂)/2 )

Midpoint = ( (2 + -4)/2 , (-2 + 6)/2 )

               =  ( (2 - 4)/2 ,  (6 - 2)/2) ) = ( -2/2,  4/2) = (-1,  2)

So the point equidistant from the two points is (-1, 2).
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Yan has already finished 3/5 of the 45 math problems he was assigned today. Each math problem took him 1 4/5 of a minute to comp
kobusy [5.1K]

Answer:

He will finish the rest of the problems in 32.4 minutes.

Step-by-step explanation:

Since we are given that Yan has completed 3/5 of 45 problems i.e.

\frac{3}{5}*45

27

Thus he has completed 27 problems

Remaining no. of problems are 45-27 = 18

Since he complete each problem in minutes = 1\frac{4}{5} =\frac{9}{5} =1.8

So, he completes 18 problems in minutes = 18 *1.8 = 32.4 minutes

Hence , He will finish the rest of the problems in 32.4 minutes.


3 0
3 years ago
190 m<br> 90 m<br> 10 m<br> 40 m<br> What is the area
liberstina [14]

Answer:

Rect Area= Lw

3D Rect Area= 2(wh+lw+lh)

Step-by-step explanation:

7 0
4 years ago
Some body can help me with a geometric mean maze
Mars2501 [29]

Answer:

See explanation

Step-by-step explanation:

Theorem 1: The length of the altitude to the hypotenuse of a right triangle is the geometric mean of the lengths of the segments of the hypotenuse.

Theorem 2: The length of each leg of a right triangle is the geometric mean of the length of the hypotenuse and the length of the segment of the hypotenuse adjacent to that leg.

1. Start point: By the 1st theorem,

x^2=25\cdot (49-25)=25\cdot 24=5^2\cdot 2^2\cdot 6\Rightarrow x=5\cdot 2\cdot \sqrt{6}=10\sqrt{6}.

2. South-East point from the Start: By the 2nd theorem,

x^2=40\cdot (40+5)=4\cdot 5\cdot 2\cdot 9\cdot 5\Rightarrow x=2\cdot 5\cdot 3\cdot \sqrt{2}=30\sqrt{2}.

3. West point from the previous: By the 2nd theorem,

x^2=(32-20)\cdot 32=4\cdot 3\cdot 16\cdot 2\Rightarrow x=2\cdot 4\cdot \sqrt{6}=8\sqrt{6}.

4. West point from the previous: By the 1st theorem,

9^2=x\cdot 15\Rightarrow x=\dfrac{81}{15}=\dfrac{27}{5}=5.4.

5. West point from the previous: By the 2nd theorem,

10^2=8\cdot (8+x)\Rightarrow 8+x=12.5,\ x=4.5.

6. North point from the previous: By the 1st theorem,

x^2=48\cdot 6=6\cdot 4\cdot 2\cdot 6\Rightarrow x=6\cdot 2\cdot \sqrt{2}=12\sqrt{2}.

7. East point from the previous: By the 2nd theorem,

x^2=22.5\cdot 30=225\cdot 3\Rightarrow x=15\sqrt{3}.

8. North point from the previous: By the 1st theorem,

x^2=7.5\cdot 36=270\Rightarrow x=3\sqrt{30}.

8. West point from the previous: By the 2nd theorem,

x^2=12.5\cdot (12.5+13.5)=12.5\cdot 26=25\cdot 13\Rightarrow x=5\sqrt{13}.

9. North point from the previous: By the 1st theorem,

12^2=x\cdot 30\Rightarrow x=\dfrac{144}{30}=4.8.

101. East point from the previous: By the 1st theorem,

6^2=1.6\cdot (x-1.6)\Rightarrow x-1.6=22.5,\ x=24.1.

11. East point from the previous: By the 2nd theorem,

20^2=32\cdot (32-x)\Rightarrow 32-x=12.5,\ x=19.5.

12. South-east point from the previous: By the 2nd theorem,

18^2=x\cdot 21.6\Rightarrow x=15.

13. North point=The end.

6 0
3 years ago
The side of a square is x, and the area is A. Express A in terms of x. Draw the graph which shows how A depends on x.
Alexandra [31]

a=x squared or x times itself

4 0
3 years ago
Beth can swim 2 laps in 7 minutes what is Beth rate in minutes per lap
Bond [772]

The answer is 1 lap/3.5 minutes

4 0
3 years ago
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