Step-by-step explanation:
The solution to this problem is very much similar to your previous ones, already answered by Sqdancefan.
Given:
mean, mu = 3550 lbs (hope I read the first five correctly, and it's not a six)
standard deviation, sigma = 870 lbs
weights are normally distributed, and assume large samples.
Probability to be estimated between W1=2800 and W2=4500 lbs.
Solution:
We calculate Z-scores for each of the limits in order to estimate probabilities from tables.
For W1 (lower limit),
Z1=(W1-mu)/sigma = (2800 - 3550)/870 = -.862069
From tables, P(Z<Z1) = 0.194325
For W2 (upper limit):
Z2=(W2-mu)/sigma = (4500-3550)/879 = 1.091954
From tables, P(Z<Z2) = 0.862573
Therefore probability that weight is between W1 and W2 is
P( W1 < W < W2 )
= P(Z1 < Z < Z2)
= P(Z<Z2) - P(Z<Z1)
= 0.862573 - 0.194325
= 0.668248
= 0.67 (to the hundredth)
Cross section is the area you make when you make a cut across a shape. In this case, the cut must be parallel to the base. Hence, the cut shape would be same to that of the base. The base's dimensions are 7 cm long x 5 cm wide. Thus, the cross section area is 35 square centimeters.
Answer:
4.4
Step-by-step explanation:
The mean is the sum of the data divided by the number of data values. so add them all together and then divide by how many numbers you added together.
Here is an example 1,3,4,5,7 so add 1+3+4+5+7=20 then you divide 20 by 5 and the mean is 4 for this example.
Answer- <em>X=12</em>
Step-by-step explanation:
X + 9/7 = 3 is our equation
Then we are going to do the opposite of dividing 7 from 9 which is multiplying 7 from 9. (on both sides)
It will leave us with - X + 9 = 21
Then we will do the opposite of adding 9 to X which is subtracting 9 from X. (also on both sides) ( whenever you do any adding or subtracting or multiplying or dividing on one side you have to do it on the other for the equation to be true)
Now it will leave us with X = 12
And that's our answer! :>
Hi! So, I don´t know the answers to this, but I think I know someone who might be able to help. Her username is IDONTLIKEUSERNAMES
Maybe message her?
