9514 1404 393
Answer:
a) V = 4w²h
b) SA = 4w² +10wh
c) SA = 4w² +37.5/w
d) C = 40w² +225/w
Step-by-step explanation:
The relevant formulas are ...
V = LWH
base area = LW
lateral area = H(2(L+W))
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a) The length is 4 times the width, so the volume is ...
V = (4w)(w)(h)
V = 4w²h
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b) The total surface area is the sum of the base area and the lateral area:
SA = base area + lateral area
SA = (4w)(w) + 2h(4w +w)
SA = 4w² +10wh
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c) The volume is 15 m³, so the height in meters in terms of the width in meters is ...
15 = 4w²h
h = 15/(4w²)
Then the surface area is ...
SA = 4w² +10w(15/(4w²))
SA = 4w² +37.5/w
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d) The equation we have for surface area has one term for base area and a second term for lateral area. We can apply the cost factors to those terms to get the cost of materials:
C = 10(4w²) +6(37.5/w)
C = 40w² +225/w
<span>overseeing the actions of brokers and financial advisers
</span><span> ensuring the security and fairness of mutual funds and exchanges
</span><span>bringing suits against businesses that are not following securities laws</span>
It is 1 because a penny is worth 1 cent.
.............................
Answer:
b. the area to the right of 2
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X, which is also the area to the left of Z. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X, which is the area to the right of Z.
In this problem:
Percentage who did better:
P(Z > 2), which is the area to the right of 2.
