How would i solvd this problem as sn improper fraction 2 1/8
2 answers:
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Answer:
The answer in the procedure
Step-by-step explanation:
The question does not present the graph, however it can be answered to help the student solve similar problems.
we know that
The equation of a vertical parabola into vertex form is equal to
where
a is a coefficient
(h,k) is the vertex
If the coefficient a is positive then the parabola open up and the vertex is a minimum
If the coefficient a is negative then the parabola open down and the vertex is a maximum
case A) we have
The vertex is the point (-4,-6)
a=3
therefore
The parabola open up, the vertex is a minimum
case B) we have
The vertex is the point (-4,-38)
a=3
therefore
The parabola open up, the vertex is a minimum
case C) we have
The vertex is the point (4,-6)
a=3
therefore
The parabola open up, the vertex is a minimum
case D) we have
The vertex is the point (4,-38)
a=3
therefore
The parabola open up, the vertex is a minimum