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8090 [49]
3 years ago
8

the length of each side of a square is 3 in. more than the length of each side of a smaller square. the sum of the areas is 45 i

n^2. find the lengths of the sides of the two squares
Mathematics
1 answer:
Marat540 [252]3 years ago
3 0

Answer:

2025 is the answer

Step-by-step explanation:

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Which fraction is equivalent to 6/8. A.8/9. B.4/6. C.9/12. D.8/10
DaniilM [7]

<u>Answer</u><u>:</u>

<h2>C. 9/12</h2>

<u>Explanation:</u>

<em>6</em><em>/</em><em>8</em><em> </em><em>simplifies </em><em>to </em><em>3</em><em>/</em><em>4</em>

<em>3</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>=</em><em> </em><em>9</em>

<em>4</em><em> </em><em>×</em><em> </em><em>3</em><em> </em><em>=</em><em> </em><em>1</em><em>2</em>

<em>Since </em><em>they </em><em>are </em><em>both </em><em>multiples </em><em>of </em><em>3</em><em>,</em><em> </em><em>it's </em><em>e</em><em>quivalent</em><em> </em><em>to </em><em>6</em><em>/</em><em>8</em><em>.</em>

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What is the distance between (-3,-4) and (5,6).
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The surface area of 2 spheres are in ration of 1:16 what is the ratio of their volume
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S1/S2 = 1/16
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Linda made $238 for 17 hours of work.
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Explain why the system has the answer given. Solve each system by elimination to prove your answer.
andrey2020 [161]

Answer:

<em>Proved below</em>

Step-by-step explanation:

<u>System of Equations</u>

There are several ways to solve a system of linear equations. One of the most-used is the method of elimination which consists in adding two or more equations to eliminate one or more variables.

The system shown in the question has evidently no solutions because we have the same variables related in the exact same way in the left side of both equations and a different number as a result of those operations.

To prove the statement, let's multiply the first equation by -1

-x-2y=-8\\x+2y=20

Adding both equations:

0=12

This false result comes from the fact that we tried to solve a system with no solutions. The only way we could have solved it is that both right sides had been equal

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