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pochemuha
4 years ago
10

PLEASE ANSWER

Mathematics
1 answer:
Lisa [10]4 years ago
6 0
Consider this solution:
1. for WX: WX=√(6²+0)=6;
for XY: XY=√(0+6²)=6;
for YZ: YZ=√(6²+0)=6;
for WZ: WZ=√(0+6²)=6.
2. Perimeter is: 6+6+6+6=24.
answer: 24
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A Web music store offers two versions of a popular song the size of the standard version is 2.7 MB the size of a high-quality ve
sertanlavr [38]

Answer:

  480

Step-by-step explanation:

Let h represent the number of high-quality downloads. Then the total download size is ...

  4.1h +2.7(1130-h) = 3723

  1.4h = 672 . . . . . . . . . . . . . . subtract 2.7·1130 = 3051

  h = 480 . . . . . . . divide by 1.4

There were 480 downloads of the high-quality version.

8 0
4 years ago
What is the volume of this rectangular prism 2/3,5,6
Fiesta28 [93]

Answer:

The volume of the rectangular prism is 20.

3 0
3 years ago
Evaluate the expression y - x + z for x = 22, y = 4, and z = 0.15
kupik [55]

Answer:

-17.85

Step-by-step explanation:

=> y-x+z

Putting y = 4, x = 22 and z = 0.15

=> 4-22+0.15

=> -18+0.15

=> -17.85

7 0
4 years ago
Read 2 more answers
Consider the probability that greater than 77 out of 131 computers will crash in a day. Assume the probability that a given comp
sweet-ann [11.9K]

Answer:

A Normal approximation to binomial cannot be applied to approximate the distribution of <em>X</em>, the number of computer crashes in a day.

Step-by-step explanation:

Let <em>X</em> = number of computers that will crash in a day.

The probability of a computer crashing in a day is, <em>p </em>= 0.99.

A random sample of <em>n</em> = 131 is selected.

A random computer crashing in a day is independent of the others.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> = 131 and <em>p</em> = 0.99.

But the sample size is quite large, i.e. <em>n</em> > 30.

So the distribution of <em>X</em> can be approximated by the normal distribution if the following conditions are fulfilled:

  • np ≥ 10
  • n(1 - p) ≥ 10

Check whether the conditions satisfy or not:

np=131\times 0.99=129.69>10\\n(1-p)=131\times (1-0.99)=1.31

The second condition is not fulfilled.

A Normal approximation to binomial cannot be applied to approximate the distribution of <em>X</em>, the number of computer crashes in a day.

6 0
3 years ago
What is4 3/4 as a improper fraction
iragen [17]
It would be 19/4.



I hope this helped you
6 0
3 years ago
Read 2 more answers
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