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pychu [463]
3 years ago
10

A new bank customer with $4,500 wants to open a money market account. The bank is offering a

Mathematics
2 answers:
viktelen [127]3 years ago
5 0

Answer:

Step-by-step explanation:

a)1.1/100 x 45000=450x1.1=495

495x20=$9,900

b) $4,500+$9,900=$14,400

Ivenika [448]3 years ago
5 0
A. 495
b. 9900
c. 1400
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What is x+x+x+x+x+x+x+x+x+x+b+b+b+b+3=
xz_007 [3.2K]

Answer:

10x+4b+3

Step-by-step explanation:

x+x+x+x+x+x+x+x+x+x+b+b+b+b+3

There are 10 x

4 b

and one number

10x+4b+3

8 0
2 years ago
Most ATM’s require a 4-digit code using the digits 0-9 how many 4-digit codes can you use
Zolol [24]

10000 digits can be used for 4 digit A.T.M code.

<u>Solution:</u>

Given that A.T.M required 4 digit codes using the digits 0 to 9.  

Need to determine how many four digit code can be used.

We are assuming that number starting with 0 are also valid ATM codes that means 0789 , 0089 , 0006 and 0000 are also valid A.T.M codes.

Now we have four places to be filled by 0 to 9 that is 10 numbers

Also need to keep in mind that repetition is allowed in this case means if 9 is selected at thousands place than also it is available for hundreds, ones or tens place .  

First digit can be selected in 10 ways that is from 0 to 9.

After selecting first digit, second digit can be selected in 10 ways that is 0 to 9 and same holds true for third and fourth digit.

So number of ways in which four digit number is created = 10 x 10 x 10 x 10 = 10000 ways

Hence 10000 digits can be used for 4 digit A.T.M code.

7 0
3 years ago
The circle below has center h. Suppose that
Mandarinka [93]
Write full questions is that....
5 0
3 years ago
How do you round 699 to the nearest tenth.
Nadusha1986 [10]
700 because the 9 in the tenth place is larger than 5
6 0
3 years ago
Help with these precalculus problems, please.
likoan [24]
Yay, easy peasy, nice refresher


53. evaluate for x=infinity
we get 100/(infiniy^2-5) which is basically 100/infinity which is a very small number so about 0



54.
vertical assemtotes, neato
that is where the denomenator equals 0
but wait, simplify first
ok, fraction is simplified (anything factored out would be a hole)
so set the denom to 0 and solve
x^2-5=0
(x-√5)(x+√5)=0
x=-√5 and √5
vertical assemtotes at x=-√5 and x=√5




55. horizontal assemtotes
for the function p(x)/f(x)

if p(x) has lower degree than f(x) then y=0 is the horizontal assemtote

if p(x) has equal degree to f(x) then divide the leading coefients of p(x) and f(x)

if p(x) has greater degree than f(x) then we got slant assemtotes

100/(x^2-5)
100 has lower degree than x^2
y=0 is the horizontal assemtote



56. evalate for x=-5
we get -150/-10=150/10=15
the limit is 15



57. that negative on the right side means that we must approach it from the left
let's see if we can factor out the denomenator
nope
so go and evaluate values like 4, 4.5, 4.9, etc, approaching x=5 from the left
we keep getting smaller and smaller valuse
this make sense because as x approaches 5, we get 30(c)/(c-5) where c is close to 5, and as c appraoches 5 very close, the top part is appraoching 150 but the bottom approaches a very small negative number, and if we do something like 150/-0.00000000001, we get a very negative number
the limit is negative infinity

alternately, you could figure that there is a vertical assemtote at x=5 so we can see that if we aproximaate closer and closer values, we get smaller values. so from what we know about assemtotes, expecially vertical ones, we say that it approaches negative infinity




58.
evalauating we get infintity/inifinty, not helpful
hmmm, is there a horizontal assemtote to help us?
the degree of top is higher so we got a slant assemtote
the only way is to use long division to divide the top by the bottom (see attachment)
we get
\frac{1}{2}x-\frac{1}{4}+\frac{\frac{1}{4}}{2x+1}
the slant assemtote is y=\frac{1}{2}x-\frac{1}{4}
as you can see, as x approaches infinity, y also will approach infinity











ANSWERS:
53. 0
54. VA is x=-√5 and x=√5
55. HA is y=0
56. the limit is 15
57. the limit is -∞
58. the limit is ∞

6 0
3 years ago
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