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3 years ago

A new bank customer with $4,500 wants to open a money market account. The bank is offering a

Mathematics

2 answers:

viktelen [127]3 years ago

5 0

Answer:

Step-by-step explanation:

a)1.1/100 x 45000=450x1.1=495

495x20=$9,900

b) $4,500+$9,900=$14,400

Ivenika [448]3 years ago

5 0

A. 495
b. 9900
c. 1400

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an isosceles triangle has congruent sides of 20cm. the base is 10cm. find the height of the triangle.

dolphi86 [110]

Answer:

$\large\boxed{A_\triangle=25\sqrt{15}\ cm^2}$

Step-by-step explanation:

Look at the picture.

The formula of an area of a triangle:

$A_\triangle=\dfrac{bh}{2}$

b - base

h - height

We need a length of a height.

Use the Pythagorean theorem:

$leg^2+leg^2=hypotenuse^2$

We have:

$leg=5,\ leg=h,\ hypotenuse=20$

Substitute:

$5^2+h^2=20^2$

$25+h^2=400$ subtract 25 from both sides

$h^2=375\to h=\sqrt{375}\\\\h=\sqrt{(25)(15)}\\\\h=\sqrt{25}\cdot\sqrt{15}\\\\h=5\sqrt{15}\ cm$

Calculate the area:

$A_\triangle=\dfrac{(10)(5\sqrt{15})}{2}=\dfrac{50\sqrt{15}}{2}=25\sqrt{15}\ cm^2$

8 0

3 years ago

alex purchased a 2010 model sedan for $24,000. The dealership offered him a $199/month payment plan for 48 months, at the end of

trapecia [35]

a = prt

a = 24,000 x 0.06 x(48 / 12)(you have to turn months into years)

a = 24,000 x 0.06 x 4

a = $5,760

The payment due is $5,760

7 0

3 years ago

Read 2 more answers

What is the GCF of 24 and 44?

mariarad [96]

write out all the factors of each number or draw out a factor tree

24:1,2,3,4,6,8,12,24

44:1,2,4,11,22

the GCF is the largest number in both the lists so in this case it is 4

6 0

3 years ago

Read 2 more answers

I need help fasttt with work

Vlad [161]

Answer:

-19.9 ft.

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Inverse laplace of [(1/s^2)-(48/s^5)]

Katen [24]

**Refresh page if you see [ tex ]**

I am not familiar with Laplace transforms, so my explanation probably won't help, but given that for two Laplace transform $F(s)$ and $G(s)$ , then $\mathcal{L}^{-1}\{aF(s)+bG(s)\} = a\mathcal{L}^{-1}\{F(s)\}+b\mathcal{L}^{-1}\{G(s)\}$

Given that $\dfrac{1}{s^2} = \dfrac{1!}{s^2}$ and $-\dfrac{48}{s^5} = -2\cdot\dfrac{4!}{s^5}$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2} - 2\cdot\dfrac{4!}{s^5}\right\} = \mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\}$

From Table of Laplace Transform, you have $\mathcal{L}\{t^n\} = \dfrac{n!}{s^{n+1}}$ and hence $\mathcal{L}^{-1}\left\{\dfrac{n!}{s^{n+1}}\right\} = t^n$

So you have $\mathcal{L}^{-1}\left\{\dfrac{1}{s^2}\right\} - 2\mathcal{L}^{-1}\left\{\dfrac{4!}{s^5}\right\} = \boxed{t-2t^4}$ .

Hope this helps...

7 0

3 years ago