Answer:
HOPE THIS HELPS
Step-by-step explanation:
The area = length * Width.
We know the width = X+6 inches and Area = x^3+3x^2–18x.
This problem can be solved just by dividing the area by width and we get a quotient as X^2–3x.
So the length is x^2–3x inches.
Answer:
please I can't do it I have not been thought
Answer-
<em>The inverse of 
is </em>
<u>Solution-</u>
The given function is,
We can get the inverse by interchanging he variable x and y among themselves and then separating each variables.
So in the inverse would be,
Taking log of both sides,
As,
Applying the same,
As,
Applying the same,
Therefore, the inverse of is 
.
First, you solve the square root:
Knowing that the square root of a negative number doesn't exist:
is your answer.
Hope it helped,
Happy homework/ study/ exam!
Since it's not mentioned I assume the Event of tossing a die twice are done simultaneously.
1- What is the theoretical probability that a coin toss results in two heads showing? I guess you mean: The theoretical probability of tossing 2 heads in 2 flips, if so P(1st Head) = 1/2 AND P(2nd Head) = 1/2, then the probability of getting 2 heads simultaneously is P(1st Head AND 2nd Head) = 1/2 x 1/2 = 1/4
2- What is the experimental probability that a coin toss results in two heads showing? In this case, I suggest that you toss a coin several times until 2 heads appear and then you calculate P: Assuming you get 2 heads (out of 10toss), the P(H) =2/10
3- What is the experimental probability that a coin toss results in two tails showing? Same logic as the previous one
4- What is the theoretical probability that a coin toss results in one head and one tail showing? If you get one Head, P(H) =1/2 and if you want a tail in the 2nd toss P(1/2). So P(one Head AND one tail) = 1/2 x 1/2 = 1/4
5- What is the experimental probability that a coin toss results in one head and one tail showing? Same as 3- or 4-
