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1 answer:
Answer:
Option C is correct
The coordinate of C' or the transformed point of C is (-6, 5)
Step-by-step explanation:
From the given graph:
In triangle ABC:
Coordinate of C is:
C(-3, 4)
The rule of transformation is given:
We have to find the coordinate of C'.
Apply the transformation on coordinate C:
Therefore, the coordinate of C' is (-6, 5)
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Answer:
hi your question options is not available but attached to the answer is a complete question with the question options that you seek answer to
Answer: v = 5v + 4u + 1.5sin(3t),
- 0
- 1
- 4
- 5
- 0
- 1.5sin(3t)
- 1
- 2.5
Step-by-step explanation:
u" - 5u' - 4u = 1.5sin(3t) where u'(1) = 2.5 u(1) = 1
v represents the "velocity function" i.e v = u'(t)
As v = u'(t)
<em>u' = v</em>
since <em>u' = v </em>
v' = u"
v' = 5u' + 4u + 1.5sin(3t) ( given that u" - 5u' - 4u = 1.5sin(3t) )
= 5v + 4u + 1.5sin(3t) ( noting that v = u' )
so v' = 5v + 4u + 1.5sin(3t)
d/dt =
+
Given that u(1) = 1 and u'(1) = 2.5
since v = u'
v(1) = 2.5
note: the initial value for the vector valued function is given as
=
