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2 years ago

Sandra decided to bake blackberry pies to sell at the county fair. She had $180 in her savings

Mathematics

1 answer:

Hatshy [7]2 years ago

6 0

Answer:

275

Step-by-step explanation:

180-130=50

25*9=225

225+50 = 275

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[Pre-Calc] Please Help! I don’t know where to start. How do I do this?

sertanlavr [38]

Answer:

See Below.

Step-by-step explanation:

Problem A)

We have:

$\displaystyle \csc^2\theta \tan^2\theta -1=\tan^2\theta$

When in doubt, convert all reciprocal trig functions and tangent into terms of sine and cosine.

So, let cscθ = 1/sinθ and tanθ = sinθ/cosθ. Hence:

$\displaystyle \left(\frac{1}{\sin^2\theta}\right)\left(\frac{\sin^2\theta}{\cos^2\theta}\right)-1=\tan^2\theta$

Cancel:

$\displaystyle \frac{1}{\cos^2\theta}-1=\tan^2\theta$

Let 1/cosθ = secθ:

$\sec^2\theta -1=\tan^2\theta$

From the Pythagorean Identity, we know that tan²θ + 1 = sec²θ. Hence, sec²θ - 1 = tan²θ:

$\tan^2\theta =\tan^2\theta$

Problem B)

We have:

$\sin^3x=\sin x-\sin x \cos^2 x$

Factor out a sine:

$\sin x(\sin^2 x)=\sin x-\sin x\cos^2 x$

From the Pythagorean Identity, sin²θ + cos²θ = 1. Hence, sin²θ = 1 - cos²θ:

$\sin x(1-\cos^2 x)=\sin x-\sin x\cos^2x$

Distribute:

$\sin x- \sin x \cos^2 x=\sin x-\sin x\cos^2 x$

Problem C)

We have:

$\displaystyle \frac{\cos 2x+1}{\sin 2x}=\cot x$

Recall that cos2θ = cos²θ - sin²θ and that sin2θ = 2sinθcosθ. Hence:

$\displaystyle \frac{\cos^2 x-\sin^2 x+1}{2\sin x\cos x}=\cot x$

From the Pythagorean Identity, sin²θ + cos²θ = 1 so cos²θ = 1 - sin²θ:

$\displaystyle \frac{2\cos^2 x}{2\sin x\cos x}=\cot x$

Cancel:

$\displaystyle \frac{\cos x}{\sin x}=\cot x$

By definition:

$\cot x = \cot x$

3 0

2 years ago

Assignment

Paul [167]

Answer:

The answer is 9.5

Step-by-step explanation: I am sure easier way of doing it but I just subtracted 64 from 73.5 and got 9.5 which was correct on edgenuity

6 0

2 years ago

What is the measure if each interior angle of a 15-gon

olya-2409 [2.1K]

Answer:

The sum of the interior angles of the 15-gon $=\:2340^0$

Each interior angle of the regular polygon $=\:156^0$

Step-by-step explanation:

As we know that

In any convex polygon, if we may start at one vertex and draw the diagonals to all the other vertices, we would form triangles,

The number of triangles thus formed would always 2 LESS than the number of sides.

The sum of measure of the angles of any triangle is 180°.

Thus,

The sum of the interior angles of the 15-gon will be:

$13\:\times\:180\:=\:2340^0$

Also

15-gon is regular, it means this total $2340^0$ is shared in equal proportion among the 15 interior angles.

And

Each interior angle of the regular polygon will be: $\frac{2340^{0} }{15}=156^{0}$

Therefore, we conclude that:

The sum of the interior angles of the 15-gon $=\:2340^0$

Each interior angle of the regular polygon $=\:156^0$

Keywords: regular polygon, 15-gon, triangle

Learn more about polygon from brainly.com/question/11932357

#learnwithBrainly

3 0

2 years ago

¼x+14 A)-3.5 B)24 C)56 D)-56

poizon [28]

Hey! I tried doing this, but there are no like terms??

3 0

2 years ago

Can sum1 help me plot the point 1/4, -2 1/4, 1 1/2?

balu736 [363]

Answer:

I do not have a graph rn but I hope I helped

Step-by-step explanation:

well, yo just have to find 0.25 on the graph, mark it then do the same for -5.25 and 5.5

3 0

2 years ago