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diamong [38]
3 years ago
8

One number is 8 times a first number. A third number is 100 more than the first number. If the sum of the three numbers is 320​,

find the numbers.
Mathematics
1 answer:
nevsk [136]3 years ago
5 0
X - the first number8x - the second numberx + 100 - the third number

The equation:
x + 8x + x + 100 = 32010x + 100 = 320    |-10010x = 220    |:10x = 22
8x = 8 · 22 = 176
x + 100 = 22 + 100 = 122
Answer: 22, 176 and 122


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solution:  option D is correct i.e., withdrawing money from savings.

explanation:

if someone is taking home loan then he has to pay it back also. but if he is withdrawing money from savings then he will don't have money to return in future. so he should save as much as he can.

so withdrawing money from savings would have a negative impact on determining eligibility for a home loan.

3 0
3 years ago
How do you write 11/25 as a percentage?
Mandarinka [93]

Answer:

44%

Step-by-step explanation:

11/25 =0.44

0.44 = 44/100 = 40%

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6 0
2 years ago
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Phil's height is 51.2 cm, suzanne's height is 5'4", and suzanne's shadow lengthat gobblers knob is 76.2
8090 [49]

Answer:

P_1 = 24cm

Step-by-step explanation:

Represent:

Phil's height with P

Suzanne's height with S

Phil's shadow with P1

Suzanne's shadow with S1

So, we have:

P = 51.2cm

S = 5'4"

S_1 = 76.2cm

Required

Calculate the length of Phil's shadow --- Missing part of question

To do this, we make use of the following equivalent ratio.

P:S = P_1 : S_1

Convert S = 5'4" to cm

S = 5ft\ 4in

S = (5*30.48+ 4*2.54)cm

S = 162.56cm

Substitute values for P, S and S1

51.2cm : 162.56cm = P_1 : 76.2cm

Express as fraction

\frac{51.2cm}{162.56cm} = \frac{P_1 }{ 76.2cm}

Make P1 the subject

P_1 = 76.2cm * \frac{51.2cm}{162.56cm}

P_1 = 76.2cm * \frac{51.2}{162.56}

P_1 = \frac{76.2cm * 51.2}{162.56}

P_1 = \frac{3901.44cm}{162.56}

P_1 = 24cm

<em>Hence, the length of Phil's shadow is 24 cm</em>

6 0
3 years ago
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Answer:

I think you mean: x^2 + 3x - 10, then

x^2 + 3x - 10

= x^2 + 5x - 2x - 10

=x(x + 5)  - 2(x + 5)

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Hope this helps!

:)

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