In this scenario we know that carbon14 at a given time A(t) = A0e^(-kt), where A0 is the original carbon present, t is time in years and k is the constant.
As we are working with the half life of carbon being 5730 years, we assume original carbon-14 content, A0 = 1, and carbon-14 at half life 5730 years, A(t) = 0.5.
i.e.
0.5 = 1e^(-5730k)
apply Ln to both sides of equation to cancel e
ln(0.5) = -5730k
k = ln(0.5) / -5730
k = -0.69315 / - 5730 = 1.20968 x 10^-4
Answer:
ok so it's telling you that for 10 folder it cost 1.50 cents each and for 20 it's 3.50 and 30 5$ and 40 6$ and it's basically telling you that what ever your reading you have to think how much did that person spend or bought and how much do u think each folder it's so u have to figure out how many does each cost of cents for each folder.
Answer: yes
Step-by-step explanation:
Answer:
0.9 ≈ 90%
Step-by-step explanation:
60% = 60/100
150% of 60% = 150/100 * 60/100
= 9000/10000
= 0.9 ≈ 90%
A. answer is: y = 13/2 OR you can say 6.5 after you simplyfi
13 over 2
b. answer is: x = 18/4 OR you can say 4.5 after you simplyfi
18 over 4
Thank you :)
bye bye later on x_x
