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3 years ago

13

Tyler is thinking of a number that is divisible by 2 and by 3. Write another number in which Tyler's number must also be divisib

le.

1 answer:

Mumz [18]3 years ago

3 0

Answer:

6

Step-by-step explanation:

6 because 6/2=3,6/3=2

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Please find the answer and explain how you found it

Zigmanuir [339]

The answer is D I made a video incase you can’t see the picture well.
Message me if you want the video.

8 0

4 years ago

Show work please<br> \sqrt(x+12)-\sqrt(2x+1)=1

Nesterboy [21]

Answer:

$x=4$

Step-by-step explanation:

Given $\displaystyle\\\sqrt{x+12}-\sqrt{2x+1}=1$ , start by squaring both sides to work towards isolating $x$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2$

Recall $(a-b)^2=a^2-2ab+b^2$ and $\sqrt{a}\cdot \sqrt{b}=\sqrt{a\cdot b}$ :

$\displaystyle\\\left(\sqrt{x+12}-\sqrt{2x+1}\right)^2=\left(1\right)^2\\\implies x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1$

Isolate the radical:

$\displaystyle\\x+12-2\sqrt{(x+12)(2x+1)}+2x+1=1\\\implies -2\sqrt{(x+12)(2x+1)}=-3x-12\\\implies \sqrt{(x+12)(2x+1)}=\frac{-3x-12}{-2}$

Square both sides:

$\displaystyle\\(x+12)(2x+1)=\left(\frac{-3x-12}{-2}\right)^2$

Expand using FOIL and $(a+b)^2=a^2+2ab+b^2$ :

$\displaystyle\\2x^2+25x+12=\frac{9}{4}x^2+18x+36$

Move everything to one side to get a quadratic:

$\displaystyle-\frac{1}{4}x^2+7x-24=0$

Solving using the quadratic formula:

A quadratic in $ax^2+bx+c$ has real solutions $\displaystyle x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$ . In $\displaystyle-\frac{1}{4}x^2+7x-24$ , assign values:

$\displaystyle \\a=-\frac{1}{4}\\b=7\\c=-24$

Solving yields:

$\displaystyle\\x=\frac{-7\pm \sqrt{7^2-4\left(-\frac{1}{4}\right)\left(-24\right)}}{2\left(-\frac{1}{4}\right)}\\\\x=\frac{-7\pm \sqrt{25}}{-\frac{1}{2}}\\\\\begin{cases}x=\frac{-7+5}{-0.5}=\frac{-2}{-0.5}=\boxed{4}\\x=\frac{-7-5}{-0.5}=\frac{-12}{-0.5}=24 \:(\text{Extraneous})\end{cases}$

Only $x=4$ works when plugged in the original equation. Therefore, $x=24$ is extraneous and the only solution is $\boxed{x=4}$

4 0

2 years ago

What is the distance between the points (-6,5) and (8,-2) on a coordinate plane?

Naddik [55]

Distance Formula: $D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2$

Apply the points: $D=\sqrt{(8-(-6))^2+((-2)-5)^2$

Solve: $D=\sqrt{(8-(-6))^2+((-2)-5)^2}\\D=\sqrt{14^2+(-7)^2}\\D=\sqrt{169+49}\\D=\sqrt{218}$

Since the square root of 218 cannot be simplified, the answer is

$D=\sqrt{218}$

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

7 0

3 years ago

Solve the equation: 2x=4

nekit [7.7K]

Answer:

x=2

Step-by-step explanation:

2x=4

x=4/2

x=2

4 0

3 years ago

Read 2 more answers

In one year, the student enrollment increased from 560 to 588. This was an increase of what percent?

sergiy2304 [10]

Answer:

5% Increase

Step-by-step explanation:

560 * 0.05 = 28

560 + 28 = 588

8 0

3 years ago

Read 2 more answers