Please help me. I need help
2 answers:
Look at the first picture.
In Quadrant II tangent is negative and cosine is negative too.
We have:

therefore we have the point (-3, 2) → x = -3 and y = 2.
Calculate r:

Calculate cosine:

Your answer is 
<h3>
Answer:</h3>
a. -(3√13)/13
<h3>
Step-by-step explanation:</h3>
The cosine can be found from the tangent by way of the secant.
tan(θ)² +1 = sec(θ)² = 1/cos(θ)²
Then ...
cos(θ) = ±1/√(tan(θ)² +1)
The <em>cosine is negative in the second quadrant</em>, so we will choose that sign.
cos(θ) = -1/√((-2/3)² +1) = -1/√(4/9 +1) = -1/√(13/9)
cos(θ) = -3/√13 = -(3√13)/13 . . . . . matches your selection A
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Minimum: 1
Q1: 2.5
Q2: 5
Q3: 7
Maximum: 13