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2 years ago

14

Graph: 20x + 3.00y is greater than or equal to 500

1 answer:

hram777 [196]2 years ago

5 0

Do you mind if I re-arrange it slightly before we solve it ?

   You said    20x + 3.00y ≥ 500

Subtract 20x
from each side:       3.00 y ≥ -20x + 500

Divide each side by 3 : y ≥ -20/3 x + 500/3

Make it an equation,
and graph this line:    y = -20/3 x + 500/3

The line is made out of all points where 'y' is EQUAL to
1/3 of (-20x + 500).

The inequality wants to see all the points that are equal to it
AND all the points that are greater than that.

So the graph of the inequality is the line AND every point that's
anywhere above the line. It's called the "half-infinite plane"
bounded by the line.

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Which equation is the inverse of y = x2 + 16?<br> 0 y=x²-16<br> y=i -16<br> y=+-16<br> y = x2 - 4

denpristay [2]

Answer:

y = ±√(x-16)

Step-by-step explanation:

To find the inverse of an equation, swap the x- and y-variables:

y = x² + 16

x = y² + 16

Then, solve for the y-variable:

x = y² + 16

y² = x - 16

y = ±√(x-16)

8 0

2 years ago

PLEASE HELP!!!!!!!!!! WILL MARK BRAINLIEST ANSWER.

Hatshy [7]

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3/100

Hopes this helps! :)

3 0

2 years ago

Read 2 more answers

option 1 drop down are: even-odd identity, quotient identity, Pythagorean identity, double-number identity.option 2 drop down ar

motikmotik

Answer:

The equation is given below as

$\frac{\cos2x}{\cos x}=\cos x-\sin x\tan x$

Step 1:

We will work on the left-hand side, we will have

$\begin{gathered} \cos x-\sin x\tan x \\ \text{recall that,} \\ Quoitent\text{ identity is} \\ \tan x=\frac{\sin x}{\cos x} \end{gathered}$

By substituting the identity above, we will have

$\begin{gathered} \cos x-\sin x\tan x=\cos x-\frac{\sin x.\sin x}{\cos x}=\cos x-\frac{\sin^2x}{\cos x} \\ \end{gathered}$

Here, we will make use of the quotient identity

Step 2:

By writings an expression, we will have

$\begin{gathered} \cos x-\sin x\tan x=\cos x-\frac{\sin x.\sin x}{\cos x} \\ \cos x-\sin x\tan x=\frac{\cos^2x-\sin^2x}{\cos x} \end{gathered}$

Here, we will use the definition of subtraction

$\cos x-\frac{\sin^2x}{\cos x}$

Step 3:

We will apply the double number identity given below

$\begin{gathered} \cos 2\theta=\cos (\theta+\theta)=\cos ^2\theta-\sin ^2\theta \\ \cos 2x=cos(x+x)=\cos ^2x-\sin ^2x \end{gathered}$

By applying this, we will have

$\frac{\cos^2x-\sin^2x}{\cos x}=\frac{\cos2x}{\cos x}$

Here, we will use the double number identity

$\frac{\cos^2x-\sin^2x}{\cos x}$

5 0

9 months ago

How to Evaluate 5/9 x 8.<br> Please answer asap (as soon as possible)

noname [10]

Answer:

5

Step-by-step explanation:

cancel the common factor of 8

4 0

2 years ago

Read 2 more answers

SOME ONE PLEASE HELP !!!!

Andrei [34K]

x = 20 - -5 = 20 + 5 = 25

y = 16 - 1 = 15

<h2>x = 25</h2><h2>y = 15</h2>

7 0

2 years ago