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Andrews [41]
3 years ago
12

the remains of an ancient ball court include a rectangular playing alley with a perimeter of about 64 M. the length of the alley

is 2 times the width. find the length and the width of the playing alley​
Mathematics
1 answer:
bezimeni [28]3 years ago
6 0

Answer:

Length =  \frac{64}{3}m

Width= \frac{32}{3}m

Step-by-step explanation:

Given

Perimeter = 64m

Length = 2 * Width

Required

Determine the length and the width

Since the alley is rectangular, the perimeter is as follows;

Perimeter = 2 (Length * Width)

Substitute 64m for Perimeter

64m = 2(Length + Width)

Substitute 2 * Width for Length

64m = 2(Width+ 2 * Width)

64m = 2(Width+ 2 Width)

64m = 2(3 Width)

64m = 6Width

Divide both sides by 6

Width= \frac{64m}{6}

Width= \frac{32}{3}m

Recall that

Length = 2 * Width

Length = 2 * \frac{32}{3}m

Length =  \frac{64}{3}m

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