Question

the remains of an ancient ball court include a rectangular playing alley with a perimeter of about 64 M. the length of the alley is 2 times the width. find the length and the width of the playing alley​

Answer 1

Answer:

$Length = \frac{64}{3}m$

$Width= \frac{32}{3}m$

Step-by-step explanation:

Given

$Perimeter = 64m$

$Length = 2 * Width$

Required

Determine the length and the width

Since the alley is rectangular, the perimeter is as follows;

$Perimeter = 2 (Length * Width)$

Substitute 64m for Perimeter

$64m = 2(Length + Width)$

Substitute 2 * Width for Length

$64m = 2(Width+ 2 * Width)$

$64m = 2(Width+ 2 Width)$

$64m = 2(3 Width)$

$64m = 6Width$

Divide both sides by 6

$Width= \frac{64m}{6}$

$Width= \frac{32}{3}m$

Recall that

$Length = 2 * Width$

$Length = 2 * \frac{32}{3}m$

$Length = \frac{64}{3}m$