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Kay [80]
3 years ago
6

Find the volume of a regular triangular pyramid if it has height h=12 cm, base edge b=10 cm and height of the triangular base hb

≈ 8.7 cm.
Mathematics
1 answer:
zzz [600]3 years ago
8 0

Answer:

it's 174

Step-by-step explanation:

Area of the base is .5 * 10 * 8.7 = 43.5

 

Volume = (1/3) * 43.5 * 12 = 174

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The local radio tower is located 20 miles east and 12 miles north of Pamela's cabin. The radio tower has a 25 mile broadcast rad
pychu [463]

Answer:

x^2 +y^2 -40x -24y  -81 =0

Step-by-step explanation:

We can write the equation of a circle in the form

(x-h)^2 + (y-k)^2 = r^2

Where (h,k) is the center and r is the radius

Assuming that Pamela's cabin is the center

( x-20)^2 + (y- 12)^2 = 25^2

We want to get to general form

x^2 + y^2 + Dx + Ey + F = 0,

Distributing

x^2 -40x +400 + y^2 -24y +144 = 625

x^2 +y^2 -40x -24y +544 -625 =0

x^2 +y^2 -40x -24y  -81 =0

3 0
3 years ago
Solve the equation on the interval [0, 2π). <br> 3(sec x)^2 -4=0
Flauer [41]

\:  \:  \:  \:  \:

x =  \frac{\pi}{6} , \frac{(k)\pi}{6} , \frac{(5)\pi}{6} , \frac{(k)\pi}{6}

<h3><em>refer</em><em> to</em><em> the</em><em> attachment</em></h3><h2><u>hope</u><u> it</u><u> helps</u></h2><h2 />

7 0
2 years ago
you want to put 520 quarters in coin wrappers. you need one wrapper for every $10 in quarters. write an equation you can use to
Lisa [10]
40c=520
This is the proper equation because there are 40 quarters in $10. Thus, if we could only fit $10 worth of quarters in each wrapper, we can only fit 40quarters in each wrapper. C represents the amount of wrappers we will need.

Hope this helps!
6 0
3 years ago
How do you evaluate<br> lim(x-&gt;0) sin(9x)/6x?
irinina [24]
Hello,
we know that lim sin x /x =1 when x->0

lim sin(9x)/6x=1/6 lim sin (9x)/ x=1/6 lim sin( 9x) /(9x)  *9=9/6=3/2

6 0
3 years ago
Determine the standard form of the equation of the line that passes through (-2, 0) and (-8, 5).
Vladimir79 [104]

Answer:

5x + 6y = -10

Step-by-step explanation:

(-2, 0) and (-8, 5)

m = (y₂ - y₁) /  (x₂ - x₁)

m = (5 - 0) / (-8 -(-2)

m = 5 / (-8+2)

m = -5/6

y = mx + b

(-8, 5)

5 = -5/6(-8) + b

5 = 40/6 + b

b = 5 - 40/6

b = -5/3

y = mx + b

y = -5/6x - 5/3           *6

6y = -5x -5(2)

6y = -5x - 10

5x + 6y = -10

8 0
3 years ago
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