Answer:
100000 pass codes
Step-by-step explanation:
the pass code form is: abcde
a: 10 numbers to choose
b: 10 numbers
c: 10 numbers
d: 10 numbers
e: 10 numbers
so there are 10^5 = 100000 pass codes exist
Answer:
15 hours
Step-by-step explanation:
Given:
Fernell's speed
mph
Dabney's speed
mph
Denote:
- distance covered by Fernell
- distance covered by Dabney
- Fernell's time
- Dabney's time
1. If Fernell drove for 3 hours longer than Dabney, then his time is 3 hours more than Dabney's time and

2. If Fernell covered 18 miles less than Dabney, then

Use formula 

Subtract from the first equation the second equation and equate it to 18:


1/4 is 25 percent so it is still 40.00
9514 1404 393
Answer:
1. ∠EDF = 104°
2. arc FG = 201°
3. ∠T = 60°
Step-by-step explanation:
There are a couple of angle relationships that are applicable to these problems.
- the angle where chords meet is half the sum of the measures of the intercepted arcs
- the angle where secants meet is half the difference of the measures of the intercepted arcs
The first of these applies to the first two problems.
1. ∠EDF = 1/2(arc EF + arc UG)
∠EDF = 1/2(147° +61°) = 1/2(208°)
∠EDF = 104°
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2. ∠FHG = 1/2(arc FG + arc ES)
128° = 1/2(arc FG +55°) . . . substitute given information
256° = arc FG +55° . . . . . . multiply by 2
201° = arc FG . . . . . . . . . subtract 55°
__
3. For the purpose of this problem, a tangent is a special case of a secant in which both intersection points with the circle are the same point. The relation for secants still applies.
∠T = 1/2(arc FS -arc US)
∠T = 1/2(170° -50°) = 1/2(120°)
∠T = 60°