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Eddi Din [679]
4 years ago
13

Find the value of x when 2x=64️️

Mathematics
1 answer:
tensa zangetsu [6.8K]4 years ago
6 0

Answer:

3

Step-by-step explanation:

divide both sides by two

2x/2=6/2

x=3

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2-^3=<br> -8<br> -6<br> -1/6<br> 1/8<br> 2/3
Allisa [31]

Answer:

-8

Step-by-step explanation:

Hope this helps!

8 0
4 years ago
One number is 16 more than another number. The two numbers have a sum of 120. Wbich system of equations could you use to find th
joja [24]

Step-by-step explanation:

Let, 1st number be x and 2nd number be y

Then,

equation 1

x = 16+y

equation 2

x + y = 120

or, y = 120 - x

now,

x = 16 + y

or, x= 16 + 120 - x (putting the value of y from equation 2 )

or, x + x = 136

or, 2x =136

or, x= 136/2

or, x =68

Then,

y = 120-x

or, y= 120- 68 (putting the value of x)

or, y= 52

Hence, the two numbers are 68 and 52.

5 0
4 years ago
Whats the slope and the equation
vichka [17]
You can find the slope of a line by having two points. In this case we have 5 different point so we pick two.

so for the first one I will pick (2,17) and (7,37)

we use (y2-y1) / (x2-x1)  this is rise over run

plug and chug to get slope.
(37-17)/(7-2)= 4 

now use point slope using one of the point that we used to find the slope
y−b=m(x−a<span>) or y-y1 = m (x-x1)

plug and chug again
m=4 ............ point (2,17)

y- 17 = 4 (x- 2)
y= 4x +10 

hope this helps
</span> 
4 0
3 years ago
Question 6( Multiple Choice Worth 1 points)
Lynna [10]

Answer:

y = 1

Step-by-step explanation:

A line with a slope of zero is a horizontal line parallel to the x- axis.

The equation of a horizontal line is

y = c

where c is the value of the y- coordinates the line passes through

The line passes through (0, 1) with y- coordinate of 1, thus

y = 1 ← is the equation of the line

8 0
4 years ago
does anybody know how the answer to this looks?
Varvara68 [4.7K]

Answer:

when x>2 (x= 3)

f(x) = -(x-2)² +1

when x = 3

f(3) = -(3-2)²+1

f(3) = -(-1)²+1

f(3) = -1+1

f(3) = 0

taking lesser value of x

makes f(x) increase

and when x>1

(x=2)

Now let's take x = 2

f(2) = -(2-2)²+1

f(2)= -(0)²+1

f(2)= 0+1 = 1

Therefore the values of x that makes f(x) = -(x-2)²+1 to increase are are (x>2 and x>1)

7 0
3 years ago
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