Answer:
3.09 miles
Step-by-step explanation:
Given one distance and two angles, we will need to use the Law of Sines. For this, we need to know the internal angles of the triangle formed by the various bearing lines.
The angle between the bearings of A and B from the transmitter will be the difference of the reverse of the given bearings.
A from T = 39.3° +180° = 219.3°
B from T = 313.9° -180° = 133.9°
Then the angle at T between receivers is ...
219.3° -133.9° = 85.4°
The angle between A and T as measured at B will be ...
313.9° -270° = 43.9°
These angles and length AB can be used with the Law of Sines to find AT:
AT/sin(B) = AB/sin(T)
AT = AB(sin(B)/sin(T)) = (4.44 mi)·sin(43.9°)/sin(85.4°)
AT ≈ 3.09 mi
The distance of the transmitter from A is about 3.09 miles.
Answer:
I want someone to help me with my question
If a chord is perpendicular to a segment drawn from the center of the circle, the intersection of the line segment to the chord bisects the chord. In other words, their point of intersection is the midpoint of the chord.
Answer:
(0,0) (-1,-1)
Step-by-step explanation: