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Zina [86]
3 years ago
5

Which statement must be true to prove m angle<1+m angle m<2+m<3=180^ ? 2 3 B A A m angle1+m angle2=180^ -m angle3; m an

gle1+m angle2=90^; m angle1=m angle2=m angle3
Mathematics
1 answer:
maria [59]3 years ago
6 0

The properties or relationship between the angles m∠1, m∠2, and m∠3 can be used to determine the statement that must be true

The correct option that gives the statement that must be true to prove that m∠1 + m∠2 + m∠3 = 180°, is the first option

A. m ║ n

Reason:

Which statement must be true to prove that m∠1 + m∠2 + m∠3 = 180°?

A. m ║ n

B. m∠1 + m∠2 = 180° - m∠3

C. m∠1 + m∠2  = 90°

D. m∠1 = m∠2 = m∠3

Given that m∠1 + m∠2 + m∠3 = 180°, we have;

m∠ACD + m∠2 + m∠3 = 180° by angles on a straight line

Therefore;

m∠ACD = m∠1 by addition property of equality

m∠ACD ≅ m∠1 by definition of congruency

m∠ACD and m∠1 are alternate interior angles formed between lines <em>m</em> and <em>n</em> and their common transversal AC

Which gives;

<em>m</em> ║ <em>n</em>, by alternate interior angles theorem which states that alternate interior formed between parallel lines are congruent

Therefore;

The statement that must be true to prove that m∠1 + m∠2 + m∠3 = 180°  is <u><em>m</em></u><u> ║ </u><u><em>n</em></u>

<em />

Learn more here:

brainly.com/question/12676838

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Help me find the answer <br>Tan 0 and Cot O ​
vesna_86 [32]

Answer:

Step-by-step explanation:

we can say the angle is also +45° going in the clock wise direction.  so take Tan(45)= 1

Cot(45) = 1

b/c  Tan(45) = Sin(45) /Cos(45) = (\sqrt{2}/2) / (\sqrt{2}/2)   ofc that's just 1

b/c Cot(45) = Cos(45) / Sin(45) , which is the same as above 1

3 0
3 years ago
If 55% of a number is 132 and 25% of the same number is 60, find 80% of that number.
UNO [17]

Answer:

  192

Step-by-step explanation:

It is always wise to look carefully at the question to see what information is given, and what information you are asked for. You are given two different fractions of the same number, and you want the value of a third fraction of that number. That third fraction is the sum of the other two.

__

The value of 80% of the number will be the sum of 55% and 25% of the number.

  n×80% = n×55% +n×25%

  n×80% = 132 +60

  n×80% = 192

80% of the number is 192.

_____

<em>Additional comment</em>

Your first clue that there may be something special about this problem lies in the fact that one fraction of a number is all you need in order to find any other fraction. Here, we're given two fractions (55% and 25%), so that is more information than we need. Why? Because it simplifies the problem to one of addition. No proportions need to be solved.

__

If you were interested, you could determine 100% of the number to be ...

  132/n = 55/100   ⇒   n = 132(100/55) = 240

or

  60/n = 25/100   ⇒   n = 60(100/25) = 240

Then ...

  0.80n = 0.80(240) = 192 . . . . 80% of the number

Or, you could write proportions for the 80% value:

  80%/55% = n/132   ⇒   n = 132(80/55) = 192 . . . . 80% of the number

  80%/25% = n/60   ⇒   n = 60(80/25) = 192 . . . . 80% of the number

__

"Look carefully" includes thinking about the ways the <em>givens</em> and the <em>finds</em> are related.

4 0
2 years ago
When it's an acute triangle what do you notice about the sum of the areas of the 2 smaller squares in relation to the area of th
Ymorist [56]
They're the same because squares have 90 degree angles and that cut in half with a diagonal would make the angle acute at a 45 degree angle so depending on the lengths of the sides depends on the area, the angles have nothing to do with it because all squared have 4 right angles
5 0
3 years ago
Find k, the constant of proportionality, for the data in this table. Then write an equation for the relationship.
VashaNatasha [74]

Answer:

k=\frac{32}{5},  y=\frac{32}{5}x

k=6.4, y=6.4x

Step-by-step explanation:

we know that

A relationship between two variables, x, and y, represent a proportional variation if it can be expressed in the form k=\frac{y}{x} or y=kx

Find the value of the constant of proportionality k

take any ordered pair from the data

For x=25, y=160

k=\frac{y}{x}

substitute the values of x and y

k=\frac{160}{25}

simplify

k=\frac{32}{5}

The linear equation is equal to

y=\frac{32}{5}x

or

y=6.4x

7 0
3 years ago
Please help me it’s math iready for a 7th grader
Artemon [7]

Answer:

m - 7.50 = 12.50

and

m = 7.50 + 12.50

Step-by-step explanation:

The best answers would be:

m - 7.50 = 12.50

and

m = 7.50 + 12.50

First of all, let's figure out what the question is asking us:

The question is asking us to find the amount of money on the gift card

It tells us to use "m" for "the amount of money on the gift card"

Now that we know the following, we can put together the equation

m = the amount of money on the gift card

$7.50 = cost of the book

$12.50 = amount remaining

Since he receives the gift card and then buys a book that costs $7.50, we are going to "have to subtract $7.50 from m". And we know that $12.50 is remaining, so we "make the equation equal to 12.50".

So, let's set up the equation:

m - 7.50 = 12.50

Now that we know the equation, we can solve for "m"

m - 7.50 = 12.50

Step 1: Add 7.50 to both sides.

m − 7.50 7.50 = 12.50 + 7.50

Step 2: Simplify

Answer: m = 20

Another way you can set up this equation is:

m = 7.50 + 12.50

Because we want to find "m", we set it equal to the equation. Since Salim bought a book for $7.50 and had $12.50 remaining, we want to find how much he had on the gift card that made him have $12.50 remaining when he bought the book. So, we have to add 7.50 and 12.50, to find how much is on the gift card.

So, the equation "m = 7.50 + 12.50", makes sense when solving for "m"

Hint: Once you have realized that the equation has Like Terms on the same side you must Combine the Like Terms by either adding them together or subtracting them.

Now that we know the equation, let's solve it

m = 7.50 + 12.50

Step 1: Combine like terms

m = (7.50 + 12.50)

m = 20

Since both equations equal $20 and both make sense, we can conclude that these are the best options.

5 0
2 years ago
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