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zavuch27 [327]
4 years ago
6

Are gases more or less dense than liquids or solids at room temperature?

Physics
1 answer:
tigry1 [53]4 years ago
8 0
<span>Solids are denser than liquids, and liquids are denser than gases at room temperature. </span>
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Mendeleev noticed that if he organized the elements by atomic weight certain patterns emerged. for instance, elements in the sam
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Properties. Each family has it's own properties, features, and even things like color, malleability, or conductivity.

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When all of the magnetic domains line up on their own, the material is called ____________________.
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Probably C...:):):):):):):):):):):):):):):):):):):):):):):):):):):):):):):):):):):)


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A basketball of mass 0.608 kg is dropped from rest from a height of 1.37 m. It rebounds to a height of 0.626 m.
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Answer:

a)|\Delta E|=4.58\: J  

b)F=61.90\: N

Explanation:

a)

We can use conservation of energy between these heights.

\Delta E=mgh_{2}-mgh_{1}=mg(h_{2}-h_{1})  

\Delta E=0.608*9.81(0.6026-1.37)

Therefore, the lost energy is:

|\Delta E|=4.58\: J  

b)

The force acting along the distance create a work, these work is equal to the potential energy.

W=\Delta E

F*d=mgh

Let's solve it for F.

F=\frac{mgh}{d}

F=\frac{0.608*9.81*1.37}{0.132}

Therefore, the force is:

F=61.90\: N

I hope is helps you!

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3 years ago
For a given Prandtl-Meyer expansion, the upstream Mach number is 3 and the pressure ratio across the wave is P2/P1 = 0.4. Calcul
loris [4]

Answer:

The angle for the forward Mach line is 19.47°

The angle for the rearward Mach line is 5.21°

Explanation:

From table A-1 (Modern Compressible Flow: with historical perspective):

\frac{P_{o} }{P_{1} } =36.73 (M₁ = 3)

If Po₁ = Po₂

\frac{P_{o2} }{P_{2} } =\frac{P_{o1} }{P_{1} } *\frac{P_{1} }{P_{2} } =36.73*\frac{1}{4} =91.825

Table A-1:

\frac{P_{o2} }{P_{2} } =91.825,M_{2} =3.63

Table A-5:

v₁ = 49.76°

μ₁ = 19.47°

v₂ = 60.55°

μ₂ = 16°

θ = 60.55 - 49.76 = 10.79°

The angle for the forward Mach line is:

μ₁ = 19.47°

The angle for the rearward Mach line is:

θr = μ₂ - θ = 16 - 10.79 = 5.21°

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