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3 years ago

What is the gravitational force on a 70.0kg object that is 3.18x106m above the earth’s surface?

Physics

1 answer:

OlgaM077 [116]3 years ago

4 0

Answer:

3' Circle the object that would exert a greater force of gravity on you. ... What is the gravitational force on a 70.0kg object sitting on the earth's surface? 8. What is ... What is the gravitational foroe on a 70.0kg object that is 3.18x106m above the.

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The required answer is 66.925 m which is the distance travelled by the car.

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Suppose the Sun were suddenly to shrink in size but that its mass remained the same. According to the law of conservation of ang

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I think its angular velocity would increase

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4 years ago

Is it (P)otential or (K)inetic energy

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4 years ago

Katelyn (55 kg) is practicing a drop jump in the biomechanics lab. She steps off a plyometrics box, lands on the force plate, an

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Answer:

J = 357.5 kg*m/s

Explanation:

The impulse exerted on Katelyn when she was on the force plate, is equal to the change in her momentum, according to Newton's 2nd Law.
Assuming as the positive direction the upward direction (coincident with the positive y-axis) we can express the initial momentum as follows:

$p_{o} = m*v_{o} = 55 kg * (-3.0 m/s) (1)$

By the same token, the final momentum is as follows:

$p_{f} = m*v_{f} = 55 kg * (3.5 m/s) (2)$

As we have already said, the impulse J is just equal to the change in momentum, i.e., the difference between (2) and (1):

$J = p_{f} - p_{o} = m* (v_{f} -v_{o}) = 55 kg* (3.5m/s- (-3.0m/s)) = 357.5 kg*m/s (3)$

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3 years ago

A student weighing 700 N climbs at constant speed to the top of an 8 m vertical rope in 10 s. The average power expended by the

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Answer:

3. 560W

Explanation:

First we calculate the work required for the 700N weigh student to climb up by 8 meters. Work is force times distance

W = Fs = 700 * 8 = 5600J

The average power is defined as the rate of energy expended over a unit of time. In order words, work divided by time duration

P = W/t = 5600 / 10 = 560 W

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3 years ago