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Liono4ka [1.6K]
2 years ago
7

Question is show below.

Mathematics
1 answer:
WITCHER [35]2 years ago
7 0

(1/4ab)^-2

Remove negative exponent by rewritten the equation as (4ab)^2

AUse Product rule to get:

4^2a^2b^2

Now raise 4 to the second power to get:

16a^2b^2


The last answer is correct.

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Volgvan

Hello,

x² + 5x + 6 = 0

a = 1 ; b = 5 ; c = 6

∆ = b² - 4ac = 5² - 4 × 1 × 6 = 25 - 24 = 1 > 0

2 solutions :

x_{1} =  \frac{ - b -  \sqrt{\Delta} }{2a}  =  \frac{ - 5 - 1}{2 \times 1}  =  \frac{ - 6}{2}  =  - 3

x_{2} =  \frac{ - b  +   \sqrt{\Delta} }{2a}  =  \frac{ - 5  + 1}{2 \times 1}  =  \frac{ - 4}{2}  =  - 2

S = { -3 ; -2}

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