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3 years ago

11

What is the difference between length and capacity?

1 answer:

AVprozaik [17]3 years ago

3 0

Answer:

length increase by the number of character append to the string. The capacity is increased only when the current capacity is exceeded by the new length

Step-by-step explanation:

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Job a pays $9.95 per hour, 40 hours per week.

OLEGan [10]

Job A pays better

there are roughly 52 weeks in a year so multiply that by 40 to get the total hours worked in a year. = 2,080

2,080 hours worked per year multiplied by the hourly pay 9.95 = 20,696

Job A pays $20,696 per year

Job B only pays $17,500

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3 years ago

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4y-14=18. Hahahahahahahaahahaha

Setler [38]

Answer:

4y = 18+14

4y = 32

y = 32/4

y = 8

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3 years ago

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What is the angle of elevation to a building that is 220 feet tall and 410 feet away?

bogdanovich [222]

Answer:

not enogh points

Step-by-step explanation:

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2 years ago

Please help i am chronically stupid

meriva

Answer:

The answer is 1.2

Step-by-step explanation:

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2 years ago

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The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation

rodikova [14]

Answer: C) $y=sin^-1 x$

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point $(1,\frac{\pi}{2})$ ,

If this point satisfies the function,

For the function $y=cos^{-1} x$

If x = 1

$y=cos^{-1}1=0$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=cos^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=cot^{-1}x$

If x = 1

$y=cot^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cot^{-1}x$ ,

⇒ The graph of $y=cot^{-1}x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=sin^{-1} x$

If x = 1

$y=sin^{-1}1=\frac{\pi}{2}$

Thus, $(1,\frac{\pi}{2})$ is satisfying function $y=sin^{-1} x$ ,

⇒ The graph of $y=sin^{-1} x$ is passing through the point $(1,\frac{\pi}{2})$ .

For the function $y=tan^{-1}x$

If x = 1

$y=tan^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=tan^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$ .

Hence, Option C is correct.

3 0

3 years ago