What is the difference between length and capacity?
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From the given table, the annual premium rate as a percentage of value insured a person at age 35 has to pay is 0.14%.
- The amount more annually a $115,000 10-year term insurance at age 35 cost Bernard than someone of the same age without health issues is option d. <u>$24</u>
Reasons:
The data in the table are presented as follows;
From the above table, we have that the amount a 35 year old without health issues will pay per $1,000 is $1.40
Therefore, the amount to be paid for $115,000 is 115 × $1.4 = $161
The amount Bernard pays = 15% more = 1.15 × $161 = $185.15
Therefore;
The amount more Bernard has to pay = $185.15 - $161 = $24.15 ≈ <u>$24</u>
Learn more about insurance premiums here:
Using the t-distribution, it is found that since the p-value of the test is of 0.0302, which is <u>less than the standard significance level of 0.05</u>, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.
At the null hypothesis, it is <u>tested if the consumption is not different</u>, that is, if the subtraction of the means is 0, hence:
At the alternative hypothesis, it is <u>tested if the consumption is different</u>, that is, if the subtraction of the means is not 0, hence:
Two groups of 22 patients, hence, the standard errors are:
The distribution of the differences is has:
The test statistic is given by:
In which is the value tested at the null hypothesis.
Hence:
The p-value of the test is found using a <u>two-tailed test</u>, as we are testing if the mean is different of a value, with <u>t = 2.2438</u> and 22 + 22 - 2 = <u>42 df.</u>
- Using a t-distribution calculator, this p-value is of 0.0302.
Since the p-value of the test is of 0.0302, which is <u>less than the standard significance level of 0.05</u>, the data provides convincing evidence that the average food intake is different for the patients in the treatment group.
A similar problem is given at brainly.com/question/25600813
9514 1404 393
Answer:
(x, y, z) = (-3, -1, 3)
Step-by-step explanation:
Many graphing calculators can solve matrix equations handily. Here, we use a combination of methods.
Use the last equation to write an expression for z.
z = 4 -x +4y
Substitute this into the second equation:
y -4(4 -x +4y) = -13
y -16 +4x -16y = -13
4x -15y -3 = 0
In genera form, the first equation can be written as ...
3x +y +10 = 0
Now, the solution to these two equations can be found to be ...
x = (-15(10) -1(-3))/(4(1) -3(-15)) = (-150 +3)/(4+45) = -3 . . . using "Cramer's rule"
y = -(10 +3x) = -(10 -9) = -1 . . . . from the first equation
z = 4 -(-3) +4(-1) = 3 . . . . . . . . from our equation for z
The solution to the system is (x, y, z) = (-3, -1, 3).
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<em>Additional comment</em>
Written as an augmented matrix, the system of equations is ...