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3 years ago

What is the difference between length and capacity?

Mathematics

1 answer:

AVprozaik [17]3 years ago

3 0

Answer:

length increase by the number of character append to the string. The capacity is increased only when the current capacity is exceeded by the new length

Step-by-step explanation:

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The graph of y = |x| is shifted to the left by 6 units.

Gnom [1K]

Answer:

D, y= |x+6|

When a graph is shifted to the left, you add the shifted value to the x value in function notation.

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3 years ago

What is 50% of $68? Show all of your work. Use the percent proportion model shown below to set up the equation before you calcul

Natali5045456 [20]

Answer:

$34

Step-by-step explanation:

50% is half of 100%

(Because 50% x 2 = 100%)

Thus, half the money ($68) to find 50%.

So, 68÷2 = 34

Final answer is $34

50/100 x $68 =$34

Hope this helps!

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2 years ago

Is 2 the solution to x to the third minus x minus 6 equals 0

Natali [406]

X actually equals the cube root of 6
${x}^{3} - 6 = 0 \\ {x}^{3} = 6 \\ x = \sqrt[3]{6}$

5 0

3 years ago

Which of the following are exterior angles? Check all that apply.

victus00 [196]

Answer:

B) ∠ 5

C) ∠ 4

F) ∠ 6

Step-by-step explanation:

you can mark the other user brainliest

8 0

3 years ago

Read 2 more answers

The population of a community is known to increase at a rate proportional to the number of people present at time t. If the popu

Lady bird [3.3K]

Answer:

$P(t) = P(0)e^{0.0693t}$

Step-by-step explanation:

The population of a community is known to increase at a rate proportional to the number of people present at time t.

This means that the population growth is modeled by the following differential equation:

$\frac{dP(t)}{dt} = rP(t)$

Which has the following solution:

$P(t) = P(0)e^{rt}$

In which P(t) is the population after t years, P(0) is the initial population and r is the growth rate.

The population has doubled in 10 years

This means that $P(10) = 2P(0)$ . We use this to find r.

$P(t) = P(0)e^{rt}$

$2P(0) = P(0)e^{10r}$

$e^{10r} = 2$

$\ln{e^{10r}} = \ln{2}$

$10r = \ln{2}$

$r = \frac{\ln{2}}{10}$

$r = 0.0693$

So the equation that will estimate the population of the community in t years is:

$P(t) = P(0)e^{0.0693t}$

6 0

3 years ago