Let "a" and "b" be some number where:
a - b = 24
We want to find where a^2 + b^2 is a minimum. Instead of just logically figuring out that the answer is where a=b=12, I'll just use derivatives.
So we can first substitute for "a" where a = b+24
So we have (b+24)^2 + b^2 = b^2 +48b +576 + b^2
And that equals 2b^2 +48b +576
Then we take the derivative and set it equal to zero:
4b +48 = 0
4(b+12) = 0
b + 12 = 0
b = -12
Thus "a" must equal 12.
So:
a = 12
b = -12
And the sum of those two numbers squared is (12)^2 + (-12)^2 = 144 + 144 = 288.
The smallest sum is 288.
Answer:
d
Step-by-step explanation:
if Emma makes 12 cupcakes and her friends eat them all, she now has 0 cupcakes.
Answer:
It is c-88=405 trust me :D
Step-by-step explanation:
*whispers* It doesn't hurt to give brainliest, I only need one more for my next tier, can I have it?
Answer:
f(32)=3
Step-by-step explanation:
once again plug 32 in for X and you end up with 3
Answer:
120 cm³
Step-by-step explanation:
6 cm·4 cm·5 cm=120 cm³
