The answer is b. In b, 10 is divided from both 90 and 60, and that's gives you 9+6.
Answer:
3.17 is the answer
Step-by-step explanation:
The answer would be true.
Answer:
A 1.9
Step-by-step explanation:
Nt = No e^(-kt)
Where Nt is the ending amount
No is the starting amount
k is the decay constant
and t is the time
We need to determine the half life
Nt/No = e ^ -kt
1/2 of the original amount is left for 1/2 life. The time is 40 years. We will calculate k
1/2 = e ^ -k * 40
Take the natural log of each side
ln(1/2) = ln (e ^ -k * 40)
ln (1/2) = -40k
-ln(2) = -40k
ln 2 = 40k
1/40 ln (2) = k
Now we can calculate now much is left after 160 years of a 30 g sample
Nt = 30 e^(- 1/40 ln(2) * 160)
= 30 e^(-4ln(2))
= 15/8
=1.875
Didn't get you question, where is the N suppose to be?
