We have solutions of 20% acid and 40% acid.
We need 60 liters of 40% acid.
"t" is liters of 20% and "f" is liters of 40%
We have to set up two equations:
A) t + f = 60
B) .20t + 1.0f = (60*.40)
Multiplying equation A) by -.2
A) -.2t -.2f = -12 then adding that to B)
B) .2t + f = (24)
.8f = 12
forty per cent volume = 15 liters
A) t + f = 60
Twenty per cent volume = 45 liters
Source:
http://www.1728.org/mixture.htm
Answer: A) 6250, 2500
<u>Step-by-step explanation:</u>
Factor the numbers. What they have in common is the GCF.
The GCF times everything leftover is the LCM.
6250: 5 × 5 × 5 × 5 × 5 × 2
2500: 5 × 5 × 5 × 5 × 2 × 2
What they have in common is the GCF:
6250: <u>5 × 5 × 5 × 5</u> × 5 × <u>2</u>
2500: <u>5 × 5 × 5 × 5</u> × 2 × <u>2</u>
GCF = 5 × 5 × 5 × 5 × 2 = 1250
GCF times everything leftover is the LCM:
6250: 5 × 5 × 5 × 5 × <u>5</u> × 2
2500: 5 × 5 × 5 × 5 × <u>2</u> × 2
LCM: 1250 × 5 × 2 = 12500
Answer:
Step-by-step explanation:
-7(x-3)
y-1+1=-7x+21
y=-7x+22
C)
f(x)= -2/3x-2
x= -3
f(0)= -2