136= 17n times 8 false true open sentence

The enrollment of a school was 1200. Since then, it has increased at a rate of 35 students per year. Write an equation to repres

Romashka [77]

The general equation to represent the enrollment of the school each year after 2000 = 1200 +35 n

where n = number of years after 2000.

Step-by-step explanation:

Here, according to the question:

The initial number of students enrolled in the school = 1200 students

The number of students increased each year = 35 students

Now if the initial year is 2000, then the number of student in the first year

= Initial enrollment + ( n x Number of students increasing each year )

where n : The total number of years after 2000

So, the number of students in first year after 2000 for n = 1 is

1200 + ( 1 x 35) = 1235

The number of students in second year after 2000 for n = 2 is

1200 + ( 2 x 35) = 1270

The number of students in third year after 2000 for n = 3 is

1200 + ( 3 x 35) = 1305

Hence, the general equation to represent the enrollment of the school each year after 2000 = 1200 +35 n where n = number of years after 2000.

4 0

2 years ago

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Here are the lowest temperatures

Masteriza [31]

The answer is (-0.7)

6 0

2 years ago

Calculate the following limit:

aleksklad [387]

$\lim_{x\to\infty}\dfrac{\sqrt x}{\sqrt{x+\sqrt{x+\sqrt x}}}=\\
\lim_{x\to\infty}\dfrac{\dfrac{\sqrt x}{\sqrt x}}{\dfrac{\sqrt{x+\sqrt{x+\sqrt x}}}{\sqrt x}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{\dfrac{x+\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{x}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\dfrac{\sqrt{x+\sqrt x}}{\sqrt{x^2}}}}=\\$
$\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{x+\sqrt x}{x^2}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\dfrac{\sqrt x}{\sqrt{x^4}}}}}=\\\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{x}{x^4}}}}}=\\
\lim_{x\to\infty}\dfrac{1}{\sqrt{1+\sqrt{\dfrac{1}{x}+\sqrt{\dfrac{1}{x^3}}}}}=\\
=\dfrac{1}{\sqrt{1+\sqrt{0+\sqrt{0}}}}=\\$
$=\dfrac{1}{\sqrt{1+0}}=\\
=\dfrac{1}{\sqrt{1}}=\\
=\dfrac{1}{1}=\\
1
$

8 0

2 years ago

Bill bought a shirt for $35.80 plus he paid an additional 7% in sales tax.

dezoksy [38]

Answer:

$2.50

Step-by-step explanation:

The cost for the shirt is 35.80

7%=0.07

35.80 x 0.07 = 2.50

Answer is $2.50

3 0

2 years ago

100 points!!!! To whoever helps me with this!

netineya [11]

Answer:

#1: Josue's dogs

#2: see images

#3: Am group median: 25.5 Pm group median: 19

#4: Am group first Quartile = 16 Pm group first Quartile = 10

#5: Am group third Quartile = 30 Pm group third Quartile = 37

#6: see images

#7: Am group Interquartile Range = 14 Pm group Interquartile Range = 27

#8: Am group because its Interquartile gruop is smaller than the Pm group

Step-by-step explanation:

Mark as Brainliest

5 0

2 years ago

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