Answer:
![[H_2]_{eq}=0.183M](https://tex.z-dn.net/?f=%5BH_2%5D_%7Beq%7D%3D0.183M)
![[I_2]_{eq}=0.183M](https://tex.z-dn.net/?f=%5BI_2%5D_%7Beq%7D%3D0.183M)
![[HI]_{eq}=0.025M](https://tex.z-dn.net/?f=%5BHI%5D_%7Beq%7D%3D0.025M)
Explanation:
Hello.
In this case, for this equilibrium problem, we first realize that at the beginning there is just HI, it means that the reaction should be rewritten as follows:
Whereas the law of mass action (equilibrium expression) is:
![Kc=\frac{[H_2][I_2]}{[HI]^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7B%5BH_2%5D%5BI_2%5D%7D%7B%5BHI%5D%5E2%7D)
That in terms of initial concentrations and reaction extent or change 
turns out:
![Kc=\frac{x*x}{([HI]_0-2x)^2}\\\\54.3=\frac{x^2}{(0.391M-2x)^2}](https://tex.z-dn.net/?f=Kc%3D%5Cfrac%7Bx%2Ax%7D%7B%28%5BHI%5D_0-2x%29%5E2%7D%5C%5C%5C%5C54.3%3D%5Cfrac%7Bx%5E2%7D%7B%280.391M-2x%29%5E2%7D)
And the solution via solver or quadratic equation is:
Whereas the correct answer is 0.183 M since the other value yield a negative concentration of HI at equilibrium (0.391-2*0.210=-0.029M).This, the equilibrium concentrations are:
![[HI]_{eq}=0.391M-2*0.183M=0.025M](https://tex.z-dn.net/?f=%5BHI%5D_%7Beq%7D%3D0.391M-2%2A0.183M%3D0.025M)
Regards.
Explanation:
The formula mass of a molecule (also known as formula weight) is the sum of the atomic weights of the atoms in the empirical formula of the compound.
a. NO2
N = 14
O = 16
NO2 = 14 + (16 * 2) = 46 amu
b. C4H10
Empirical formular = C2H5
C = 12
H = 1
C2H5 = (12*1) + (1*5) = 12 + 5 = 17 amu
c. C6H12O6
Empirical formular = CH2O
C = 12
H = 1
O = 16
C2H5 = 12 + (1*2) + 16 = 30 amu
d MgBr2
Mg = 24
Br = 80
MgBr2 = 24 + (80*2) = 184 amu
e. HNO2
H = 1
N= 14
0 = 16
HNO2 = 1 + 14 + (16*2) = 47 amu
f. CBr4
C= 12
Br = 80
CBr4 = 12 + (80*4) = 332 amu
g. Cr(NO3)3
Cr = 52
N = 14
O = 16
Cr(NO3)3 = 52 + 3[14 + (3*16)] = 238 amu
Answer:
The pressure of the gas is 224839.8 atm
Explanation:
As we know
PV = nRT
Substituting the given values, we get -
P * 1 L = 90.1 moles * 8.314 4621(75). J K−1 mol−1 * 300
P = 224839.8 atm
The pressure of the gas is 224839.8 atm
Marshmallows contain mostly water and sugar. When microwaved, the water heats up, so do the air bubbles in the marshmallow, and they thus take more space. Since sugar tends to soften when heated up, the marshmallow's structure will puff up as the air bubbles expand.
Answer:
Option 3 is correct.
The atomic nucleus of each element has a unique number of protons. Therefore, the energy of the electron layers of the atoms of each element is unique.
If we have the energy released from each electron transfer between the layers of the atom, we can identify the element.
