Answer:
1.977 g/L
Nitrous oxide
Names
Molar mass 44.013 g/mol
Appearance colourless gas
Density 1.977 g/L (gas)
Melting point −90.86 °C (−131.55 °F; 182.29 K)
Answer:
Rate law: = ![k[CS_2]^1](https://tex.z-dn.net/?f=k%5BCS_2%5D%5E1)
Explanation:
Given:
t ![[CS_2]](https://tex.z-dn.net/?f=%5BCS_2%5D)
0.100 
0.080 
0.055 
0.044 
Rate law for the given reaction: ![k[CS_2]^n](https://tex.z-dn.net/?f=k%5BCS_2%5D%5En)
Where, n is the order of the reaction.
Divide rate 1 with rate 3
![\frac{0.100}{0.055} =\frac{k[CS_2 (1)]^n}{k[CS_2 (3)]^n} \\\frac{0.100}{0.055} =\frac{k[2.7 \times 10^{-7}]^n}{k[1.5\times 10^{-7}]^n}\\1.81=[1.8]^n\\ n=1](https://tex.z-dn.net/?f=%5Cfrac%7B0.100%7D%7B0.055%7D%20%3D%5Cfrac%7Bk%5BCS_2%20%281%29%5D%5En%7D%7Bk%5BCS_2%20%283%29%5D%5En%7D%20%5C%5C%5Cfrac%7B0.100%7D%7B0.055%7D%20%3D%5Cfrac%7Bk%5B2.7%20%5Ctimes%2010%5E%7B-7%7D%5D%5En%7D%7Bk%5B1.5%5Ctimes%2010%5E%7B-7%7D%5D%5En%7D%5C%5C1.81%3D%5B1.8%5D%5En%5C%5C%20n%3D1)
So, rate law = ![k[CS_2]^1](https://tex.z-dn.net/?f=k%5BCS_2%5D%5E1)
Whenever a sports person engages in a physical activity, there is a lot of sweat. The sweat causes loss of water and electrolytes in the body. So, both need to be restored back to the required amount in the body.
ELECTROLYTES AND WATER.