In Section 5.6, we learned that triple bonds are stronger and shorter than single bonds. For example, a C−CC−C single bond has a
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Answer:
Explanation:
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In this case, since the reaction for the formation of ammonia is:
We can evidence the 1:2 mole ratio of nitrogen gas to ammonia; therefore, the appropriate stoichiometric setup for the calculation of the moles of the latter turns out to be:
And the result is:
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