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maw [93]
3 years ago
10

SOLVE THIS QUESTION​

Mathematics
2 answers:
Anettt [7]3 years ago
7 0
447/250 that’s the correct answer hope that helped you
ASHA 777 [7]3 years ago
4 0

447/250

is the answer to the question

You might be interested in
The nth term of a sequence is 3n2 what is the term in the sequence with a value greater with 1000
Dmitriy789 [7]

Answer:

19 > 1083

Step-by-step explanation:

Given: The nth term of a sequence is given by .  

let βn be the nth term.

           then βn = 3n²

Let x be the term which is the first one with a value greater than 1000.

19 th term is the first one with a value greater than 1000 the sequence that is βx > 1000

         3x² > 1000

divide by 3

           3x²/3 > 1000/3

            x² > 1000/3

            x² > 333.33.....

to make x the subject of the formula, square root both sides

√x² > √333.333

the square cancel the square root at x

x > √333.333

x>18.257

x > 19 approximately

19 th term is the first one with a value greater than 1000 the sequence.

that is: β19 = 3(19)²

            3(316)²

               =1083.

Hope it will help.


6 0
3 years ago
A solid figure has 2 flat surfaces. 1 curved surface, no edges and no vertices. Name this soild figure
ikadub [295]

Answer:

cylinder

Step-by-step explanation:

the two flat surfaces are the circles on the top, and the curved surface is it's "body"

5 0
3 years ago
Read 2 more answers
Select the correct answer.
Inessa [10]
I think its a :) if not c
6 0
2 years ago
Anyone know the answer?
sattari [20]
The answer is c because k and m are the same so l and n are also the same


7 0
3 years ago
Match each expression in the left column with the correct product in the right column.
lesya692 [45]

Answer:

-6

-6i

6i

6

Step-by-step explanation:

1) √4 . √-3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2 $

$ \sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 = $ -6

2) √-4 . √-3 . √-3

$ \sqrt{-4} = 2i $ .

Therefore, $ \sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1}  \times -3 = 2i \times (-3) =  $ - 6i

3) √4 . √3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{-3} = (\sqrt{3})^2 . \sqrt{-1} $

$ \implies 2 \times 3i = $ 6i

4) √4 . √3 . √3

$ \sqrt{4} = 2 $

$ \sqrt{3} . \sqrt{3} = (\sqrt{3})^2  = 3 $

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0
3 years ago
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