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Zolol [24]
3 years ago
7

Jordan solved the equation −7x + 25 = 48; his work is shown below. Identify the error and where it was made. −7x + 25 = 48 Step

1: −7x + 25 − 25 = 48 − 25 Step 2: −7x = 23 Step 3: negative seven times x over seven = twenty-three over seven Step 4: x = twenty-three over seven
Mathematics
2 answers:
mixas84 [53]3 years ago
3 0
The problem seems to be correct there should be there aren't any mistakes right?
DanielleElmas [232]3 years ago
3 0

Answer:

The error was that Jordan didn't take into account the minus sign in the step 3. The solution of the equation is x=-\frac{23}{7}

Step-by-step explanation:

The steps to solve the equation -7x+25=48 would be:

  1. -7x+25-25=48-25,          the step 1 is correct.
  2. -7x=23,          the step 2 is correct
  3. \frac{-7x}{7}=\frac{23}{7},          the step 3 is correct.
  4. x=\frac{23}{7},           the step 4 is INCORRECT

The step 4 is incorrect because the minus sign in the step 3 was not taken into account. The correct steps would be:

  1. -7x+25-25=48-25
  2. -7x=23
  3. \frac{-7x}{7}=\frac{23}{7}
  4. -x=\frac{23}{7}
  5. -x\cdot (-1)=\frac{23}{7}\cdot (-1)
  6. x=-\frac{23}{7}

Thus, the error was that Jordan didn't take into account the minus sign in the step 3. The solution of the equation is x=-\frac{23}{7}

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X^4=15 <br> is an exponential equation?
miskamm [114]

Answer:

No. It is not an Exponential Equation.

Step-by-step explanation:

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By the Definition of Exponential Equation which states.

"The equation is said to be an exponential equation when it has a variable occurred in the exponent and which have the same base."

For Example:

All given below are said to be exponential equations.

5^{x} =5^{2} \\7^{x}=49\\

which can be rewritten as

7^{x}=7^{2}

Now in the given equation x^{4}=15 it doesn't have same base neither any means the base can be made same,hence the given equation is not an exponential equation

8 0
3 years ago
Can I please get an explanation and answer for this problem.
Gnom [1K]

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132 degrees

Step-by-step explanation:

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7 0
3 years ago
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To evaluate log2(3), Autumn reasoned that since log2(2) = 1 and log2(4) = 2, log2(3) must be the average of 1 and 2 and therefor
geniusboy [140]

Answer:

log₂(3) = 1.585 ≠ 1.5

Her thinking is not valid because the technique of average is valid only  if the graph of the function is a straight line, but the graph of the log function is not a straight line.

Therefore the values cannot be taken by average

Step-by-step explanation:

Given:

log₂(2) = 1

log₂(4) = 2

To evaluate :  log₂(3)

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we know that

logₓ(y) = \frac{\log(y)}{\log(x)}        (Here the log has same base in the numerator and the denominator i.e 10)

therefore,

log₂(3) =  \frac{\log(3)}{\log(2)}

also,

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thus,

log₂(3) =  \frac{0.4771}{0.3010}

or

log₂(3) = 1.585 ≠ 1.5

Her thinking is not valid because the technique of average is valid only  if the graph of the function is a straight line, but the graph of the log function is not a straight line.

Therefore the values cannot be taken by average

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3 years ago
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Answer:

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