Ask question

Ask question

All categories

3 years ago

7

everything 3 days seth goes to the grocery store his best friend brian goes 5 days on what day will they both go on to the store

on the same day

1 answer:

7nadin3 [17]3 years ago

3 0

Wednesday??????????????????????????????????????

You might be interested in

J.J.Bean sells a wide variety of outdoor equipment and clothing. The company sells both through mail order and via the internet.

melamori03 [73]

Answer:

99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

Step-by-step explanation:

We are given that a random sample of 16 sales receipts for mail-order sales results in a mean sale amount of $74.50 with a standard deviation of $17.25.

A random sample of 9 sales receipts for internet sales results in a mean sale amount of $84.40 with a standard deviation of $21.25.

The pivotal quantity that will be used for constructing 99% confidence interval for true mean difference is given by;

P.Q. = $\frac{(\bar X_1-\bar X_2)-(\mu_1-\mu_2)}{s_p \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ ~ $t__n_1_+_n_2_-_2$

where, $\bar X_1$ = sample mean for mail-order sales = $74.50

$\bar X_2$ = sample mean for internet sales = $84.40

$s_1$ = sample standard deviation for mail-order purchases = $17.25

$s_2$ = sample standard deviation for internet purchases = $21.25

$n_1$ = sample of sales receipts for mail-order purchases = 16

$n_2$ = sample of sales receipts for internet purchases = 9

Also, $s_p =\sqrt{\frac{(n_1-1)\times s_1^{2}+(n_2-1)\times s_2^{2} }{n_1+n_2-2} }$ = $\sqrt{\frac{(16-1)\times 17.25^{2}+(9-1)\times 21.25^{2} }{16+9-2} }$ = 18.74

The true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is represented by ( $\mu_1-\mu_2$ ).

Now, 99% confidence interval for ( $\mu_1-\mu_2$ ) is given by;

= $(\bar X_1-\bar X_2) \pm t_(_\frac{\alpha}{2}_) \times s_p \times \sqrt{\frac{1}{n_1} +\frac{1}{n_2}}$

Here, the critical value of t at 0.5% level of significance and 23 degrees of freedom is given as 2.807.

= $(74.50-84.40) \pm (2.807 \times 18.74 \times \sqrt{\frac{1}{16} +\frac{1}{9}})$

= [$-31.82 , $12.02]

Hence, 99% confidence interval for the true mean difference between the mean amount of mail-order purchases and the mean amount of internet purchases is [$(-31.82) , $12.02].

5 0

3 years ago

Elena’s dad buys another type of cell phone that also usually sells for $250. He pays 75% of the usual price. How much did he pa

Mademuasel [1]

Elena’s dad paid $187.5.

8 0

3 years ago

Mean and median height: An association of U.S. dog breeders reported in a recent year that the mean height for their adult dogs

Ray Of Light [21]

Answer:

We should expect the histogram to be skewed to the right.

Step-by-step explanation:

The median separates the upper half from the lower half of a set. So 50% of the values in a data set lie at or below the median, and 50% lie at or above the median.

The mean is the average of all the values in the set.

Median, mean and skewness of the histogram:

If the mean is greater than the median, the histogram has positive skewness, that is, it is skewed to the right.

If the mean is lesser than the median, the histogram has negative skewness, that is, it is skewed to the left.

If the mean and the median are equal, the histogram is approximately symmetric.

In this problem, we have that:

Mean = 22

Median = 15.9

So we should expect the histogram to be skewed to the right.

7 0

3 years ago

riadik2000 [5.3K]

Answer:

11/4 = 5/4

If you need 5/4 cups of sugar to make 20 cookies or in other words,

For 20 cookies you need 5/4 cups of sugar then

for 14 cookies you will need: 14 * (5/4)/20 = 7/8 cups of cookies

if you like a very sweet cookies then you can add a bit more sugar to make it 1 full cup of suger

6 0

3 years ago

Suppose you want to fly for a party. Three rolls of streamers and 15 party hats cost $30. Larry, you've got two rolls of streame

aleksklad [387]

Answer:

Each steamer costs $2.5 and each party hat costs $1.5

Step-by-step explanation:

Let the cost of 1 steamer =x

Let the cost of 1 party hat =y

Three rolls of streamers and 15 party hats cost $30

3x+15y=30

Two rolls of streamers and four party hats for $11.

2x+4y=11

We solve the two equations simultaneously.

Multiply equation 1 by 2 and equation 2 by 3

6x+30y=60

6x+12y=33

Suntract

18y=27

y=1.5

From 6x+30y=60

6x+30(1.5)=60

6x+45=60

6x=60-45=15

x=2.5

Since x=2.5 and y=1.5

Each steamer costs $2.5 and each party hat costs $1.5

5 0

3 years ago

Read 2 more answers