Semi circle diameter is 8 what is the area
2 answers:
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Answer:
\sqrt{6}
Explanation:
From the given diagram,
Hypotenuse sde = x
Opposite side = \sqrt{3}
Using the SOH CAH TOA identity
Sintheta = opposite/hypotenuse
Sin 45 = \sqrt{3}/x
x = \sqrt{3}/sin45
Hence the value of x is \sqrt{6}
