Since in the above case, the beaker has two sections each with different radius and height, we will divide this problem into two parts.
We will calculate the volume of both the beakers separately and then add them up together to get the volume of the beaker.
Given, π = 3.14
Beaker 1:
Radius (r₁) = 2 cm
Height (h₁) = 3 cm
Volume (V₁) = π r₁² h₁ = 3.14 x 2² x 3 = 37.68 cm³
Beaker 2:
Radius (r₂) = 6 cm
Height (h₂) = 4 cm
Volume (V₂) = π r₂² h₂ = 3.14 x 6² x 4 = 452.16 cm³
Volume of beaker = V₁ + V₂ = 37.68 + 452.16 = 489.84 cm³
Answer:
x=5
Step-by-step explanation:
If the sum of the measures of angle M and R is 90 degrees, and you know that angle R is 55 degrees, subtract angle R from the total angle. Then, solve for M
90 - 55 = 35
5x + 10 = 35
5x = 25
x = 5
<span><span>n<span>x4/</span></span>5</span>=<span>3/<span>4
</span></span><span><span><span><span>1/5</span><span>n<span>x^4</span></span></span><span><span>x^4/</span>5</span></span>=<span><span>3/4</span><span><span>x^4/</span>5</span></span></span><span>
Answer is n=<span>15/<span>4<span>x<span>4</span></span></span></span></span>
Answer:
true duhh :))
Step-by-step explanation:
Answer:
-24 = -0.6k
k=-24/-0.6
k=40
Let me know if this helps!
