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telo118 [61]
2 years ago
9

Of the 58 employees in a firm, 8 are considered support staff, and 7 of the employees have more than five years of experience. A

ll of the support staff
have less than five years of experience. Consider the two events, J and K.
• Event J: Employee is considered support staff.
• Event K: Employee has more than five years of experience.
How many outcomes are possible for the complement of the union of Events J and K?

Mathematics
1 answer:
polet [3.4K]2 years ago
6 0

Using statistical concepts, it is found that the number of outcomes that are possible for the complement of the union of Events J and K is of 43.

<h3>What is the union of events J and K?</h3>

It means that at least one of event J or event K is true, hence, it is composed by employees that are either considered support staff(less than 5 years of experience) or employees that have more than five years of experience, combining a total of 7 + 8 = 15 employees.

<h3>What is the complement?</h3>

The total number of outcomes of the union of J and K, plus the complement, add to the total number of 58, hence:

15 + x = 58

x = 43.

The number of outcomes that are possible for the complement of the union of Events J and K is of 43.

More can be learned about complementary events at brainly.com/question/9752956

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What is the mean absolute deviation of this data set? 26, 31, 32, and 39
Nezavi [6.7K]

Answer:

3.5

Step-by-step explanation:

26, 31, 32, and 39

First we need to find the mean

(26+ 31+ 32+ 39) /4

128/4 = 32

The mean absolute deviation is sum of   the positive difference between the number and the mean  divided by the number of terms

((32-26)+ (32-31)+ (32-32)+ (39-32)) /4

14/4

3.5

4 0
3 years ago
Janice gives Rs 215.50 to Mia. if she started with Rs 403.75.how much money does she have left​
stellarik [79]

Answer:

188.25

Step-by-step explanation:

Okay, so. He had 403.75. He gives 215.50 to Mia. So, we would subtract it.

403.75 - 215.50 = 188.25

Therefore they will have 188.25 left.

7 0
4 years ago
There are 4 aces and 4 kings in a standard deck of playing cards. you pick one random card at random. What is the probability of
hichkok12 [17]

Answer:2/3

Step-by-step explanation:There are 52 cards in a standard deck: 13 ordinal cards (Ace - 10, Jack, Queen, King) and 4 of them - one to each suit (hearts, diamonds, clubs, spades) and so we have

4

×

13

=

52

.

There are 8 cards that fit the question (4 each of aces and kings).

And so in a random draw, the odds of drawing one of those 8 cards out of the total number of 52 is:8/52

which we can simplify:

8/52=2/13

8 0
2 years ago
Which equation is a quadratic model for the data set? Hint: Use a graphing calculator or a spreadsheet program.
Ivahew [28]

The equation that model a quadratic function is:  y=0.9673x²-0.8475x+10.4334

Step-by-step explanation:

A quadratic function has the form of ;

f(x) = ax²+bx+c  where a, b and c are real numbers and a≠0

For this case, equation y=0.9673x²-0.8475x+10.4334 models a quadratic function where a>0 thus the parabola opens upwards

See attached figure below to visualize the graph

Learn More

Quadratic functions graphs: brainly.com/question/9048896

Keywords : equation, quadratic model, data set, calculator, spreadsheet program.

#LearnwithBrainly

4 0
3 years ago
What is the benchmark of 6/10
IceJOKER [234]
First split your model into 10 equal sections then you shade/color in 6 of them.
There it goes that is 6/10 bench mark!
~JZ
Hope it helps
3 0
3 years ago
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