Given, a parking lot charges $3 for first hour and $2 per hour after that.
So for t hours, the parking lot charges $3 for the first hour and after first hour there is 
hours left.
So for hours it will charge $2 per hour.
The charges for hours = $
.
Total charges for t hours for one car = $
Now for the second car, it will charge 75% of the first car.
So the charges for second car
=$[ 
]
=$
There are 3 cars. That parking charges for the third car is also 75% of the first car.
So for third car the parking charges are same as for the second car.
Total parking charges for 3 cars
= $
= $
We have got the required answer here.
The correct option is option C.
The number of presale tickets sold is 271
<em><u>Solution:</u></em>
Let "p" be the number of presale tickets sold
Let "g" be the number of tickets sold at gate
<em><u>Given that, total of 800 Pre-sale tickets and tickets at the gate were sold</u></em>
Therefore,
Presale tickets + tickets sold at gate = 800
p + g = 800 ------ eqn 1
<em><u>Given that, number of tickets sold at the gate was thirteen less than twice the number of pre-sale tickets</u></em>
Therefore,
Number of tickets sold at gate = twice the number of pre-sale tickets - 13
g = 2p - 13 ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
Substitute eqn 2 in eqn 1
p + 2p - 13 = 800
3p -13 = 800
3p = 800 + 13
3p = 813
p = 271
Thus 271 presale tickets were sold
