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postnew [5]
3 years ago
13

2t−5=−10 what is t I really need help

Mathematics
2 answers:
geniusboy [140]3 years ago
8 0
2t - 5 = -10
2t = -10 + 5
t = -5/2

In short, Your Answer would be -5/2

Hope this helps!
Galina-37 [17]3 years ago
5 0
t = -2.5 or -\frac{5}{2}

Here's how we find that out:

2t -5 = -10..........................We need to get the variable, t, by itself

2t = -5................................Add 5 to both sides

t = -2.5...............................Divide both sides by 2

So, your answer is - \frac{5}{2} 0r -2.5

I hope this helped! Have a great day! :))
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Suppose that we are testing H0 : 0 versus H1 : 0 with a sample size of n 10. Calculate bounds on the P-value for the following o
stepan [7]

Answer:

a) p_V = 2*P(t_{9} >|2.48|) =0.0349

We can use the following excel code: "=2*(1-T.DIST(2.48,9,TRUE))"

0.03 < p_v

b) p_V = 2*P(t_{9} >|-3.95|)=0.003355

We can use the following excel code: "=2*(1-T.DIST(3.95,9,TRUE))"

p_v

c) p_V = 2*P(t_{9} >|2.69|) =0.02480

We can use the following excel code: "=2*(1-T.DIST(2.69,9,TRUE))"

0.01 < p_v

d) p_V = 2*P(t_{9} >|1.88|) =0.09281

We can use the following excel code: "=2*(1-T.DIST(1.88,9,TRUE))"

0.05 < p_v

Step-by-step explanation:

For this case we are testing the following system of hypothesis:

Null hypothesis: \mu =0

Alternative hypothesis: \mu \neq 0

The sample size is n=10, so then the degrees of freedom are given by:

df=n-1= 10-1=9

In order to calculate the p value we can use the fact that we are conducting a bilateral test so then the p value is given by:

p_V = 2*P(t_{9} >|t_0|)

Where t_0 represent the calculated or observed statistic.

a) t0= 2.48

p_V = 2*P(t_{9} >|2.48|) =0.0349

We can use the following excel code: "=2*(1-T.DIST(2.48,9,TRUE))"

0.03 < p_v

b) t0= -3.95

p_V = 2*P(t_{9} >|-3.95|)=0.003355

We can use the following excel code: "=2*(1-T.DIST(3.95,9,TRUE))"

p_v

c) t0=2.69

p_V = 2*P(t_{9} >|2.69|) =0.02480

We can use the following excel code: "=2*(1-T.DIST(2.69,9,TRUE))"

0.01 < p_v

d) t0=1.88

p_V = 2*P(t_{9} >|1.88|) =0.09281

We can use the following excel code: "=2*(1-T.DIST(1.88,9,TRUE))"

0.05 < p_v

6 0
3 years ago
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