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postnew [5]
3 years ago
13

2t−5=−10 what is t I really need help

Mathematics
2 answers:
geniusboy [140]3 years ago
8 0
2t - 5 = -10
2t = -10 + 5
t = -5/2

In short, Your Answer would be -5/2

Hope this helps!
Galina-37 [17]3 years ago
5 0
t = -2.5 or -\frac{5}{2}

Here's how we find that out:

2t -5 = -10..........................We need to get the variable, t, by itself

2t = -5................................Add 5 to both sides

t = -2.5...............................Divide both sides by 2

So, your answer is - \frac{5}{2} 0r -2.5

I hope this helped! Have a great day! :))
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What is -3(2 - x) = 9x​
Romashka [77]

Answer:

-1=x

Step-by-step explanation:

You multiply the -3 into the (2-x). which gives you -6+3x=9x. Know you wanna get ride of the 3x so you subtract from both sides, which then gives you. -6=6x. From here were gonna need to get x by itself so you divide both  sides by 6.

4 0
4 years ago
Read 2 more answers
You have 8,640 grams of a radioactive kind of cesium. If its half-life is 30 years, how much
Vikki [24]

The mass of cesium left afer 120 years if the original mass of cesium is 8640 with an half-life of 30 years,  is 540 grams.

<h3>What is half-life?</h3>

This can be defined as the time taken for half the amount of a radioactive substance to decay.

To calculate the amount of cesium left after 120 years, we use the formua below.

Formula:

  • R' = R/(2^{T/t})............. Equation 1

Where:

  • R = Original amount of Cesium
  • R' = New amount of cesium
  • T = Total time
  • t = Half-life

From the question,

Given:

  • R = 8640
  • T = 120 years
  • t = 30 years

Substitute these values into equation 1

  • R' = 8640/(2^{120/30})
  • R' = 8640/2^{4}
  • R' = 8640/16
  • R' = 540 grams.

Hence, The mass of cesium left afer 120 years is 540 grams.

Learn more about half-life here: brainly.com/question/25750315

4 0
2 years ago
Use the figure to the right to find the value of PT. Pt=4x + 9 and TQ= 6x - 5
zhuklara [117]

Answer:

The answer is

Step-by-step explanation:

PT 4x+9

TQ 6x-5

PT 13x

TQ 1x

The value of PT is 13 x

6 0
3 years ago
Could I get the awnser and explanation of this? Thank you!
astra-53 [7]

Answer:

equation: y = 4x-12

slope: 4

y-intercept: -12

Step-by-step explanation:

3 points across an x-axis is +1 x-axis difference and +4 y-axis away from origin, so you have to subtract 3 by 1 andsubtract y by 4. until x is 0, you get -12 on y-axis

6 0
3 years ago
Calculate the rise and run and find the slope ( (4,-7) and (4,0)
Marta_Voda [28]
Hey there! :D

Slope formula:

m= (y2-y1)/(x2-x1)

m= (0-(-7)/(4-4)

m=0+7/0

m=7/0

The rise is 7 and the run is 0.

I hope this helps!
~kaikers
7 0
3 years ago
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