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Misha Larkins [42]
3 years ago
13

20 characterssssssss

Mathematics
1 answer:
Arte-miy333 [17]3 years ago
4 0
Draw 6 “C” pucks
And draw 8 regular pucks representing the other wins not by Colin.
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An investigator compares the durability of two different compounds used in the manufacture of a certain automobile brake lining.
strojnjashka [21]

Answer:

1. The 90% confidence interval for the true difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2 is (-2411.84, -1332.16).

2. The point estimate for the true difference between the population means is of -1872.

Step-by-step explanation:

Before building the confidence interval, we need to understand the central limit theorem and subtraction between normal variables.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a normally distributed random variable X, with mean \mu and standard deviation \sigma, the sampling distribution of the sample means with size n can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}.

For a skewed variable, the Central Limit Theorem can also be applied, as long as n is at least 30.

Subtraction of Normal Variables:

When two normal variables are subtracted, the mean is the subtraction of the means while the standard deviation is the square root of the sum of the variances.

A sample of 212 brakes using Compound 1 yields an average brake life of 47,895 miles. The population standard deviation for Compound 1 is 1590 miles.

This means that \mu_1 = 47895, \sigma_1 = 1590, n = 212, s_1 = \frac{1590}{\sqrt{212}} = 109.2

A sample of 180 brakes using Compound 2 yields an average brake life of 49,767 miles. The population standard deviation for Compound 2 is 4152 miles.

This means that \mu_2 = 49767, \sigma_2 = 4152, n = 180, s_2 = \frac{4152}{\sqrt{180}} = 309.47

True difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2.

This is the distribution 1 - 2. So

\mu = \mu_1 - \mu_2 = 47895 - 49767 = -1872

This is also the point estimate for the true difference between the population means, which is question 2.

s = \sqrt{s_1^2+s_2^2} = \sqrt{109.2^2+309.47^2} = 328.17

90% confidence interval

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = zs = 1.645*328.17 = 539.84

The lower end of the interval is the sample mean subtracted by M. So it is -1872 - 539.84 = -2411.84

The upper end of the interval is the sample mean added to M. So it is -1872 + 539.84 = -1332.16.

The 90% confidence interval for the true difference between average lifetimes for brakes using Compound 1 and brakes using Compound 2 is (-2411.84, -1332.16).

5 0
3 years ago
The perimeter of a square is 3 1/3 mi, and its side is 5/6 mi. Find its area
pychu [463]
Area = side * side
5/6 * 5/6
= 25/36
6 0
4 years ago
Need helppp!! an explanation appreciated!
AysviL [449]

Answer: Thanks  can i get my first brainilst

Step-by-step explanation: its d they flippend the grid around the answer is D

8 0
3 years ago
Which pair of angles are supplementary?
NemiM [27]

Answer:

1 and 7

Step-by-step explanation:

supplementary means that they add up to 180º

1,3                    5,6              1,7          

2,4                   7,8              2,8

1,2                    5,7              3,5

3,4                   6,8              4,6

There are still some more but my hands are tired of typing.

4 0
3 years ago
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The two dot plots below compare the forearm lengths of two groups of schoolchildren:
Amanda [17]
The answer to your question is option B
4 0
2 years ago
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