Answer:
109.32 N/m
Explanation:
Given that
Mass of the hung object, m = 8 kg
Period of oscillation of object, T = 1.7 s
Force constant, k = ?
Recall that the period of oscillation of a Simple Harmonic Motion is given as
T = 2π √(m/k), where
T = period of oscillation
m = mass of object and
k = force constant if the spring
Since we are looking for the force constant, if we make "k" the subject of the formula, we have
k = 4π²m / T², now we go ahead to substitute our given values from the question
k = (4 * π² * 8) / 1.7²
k = 315.91 / 2.89
k = 109.32 N/m
Therefore, the force constant of the spring is 109.32 N/m
Answer: Your answer is 1250J
Explanation:
K
E
=
1/2
m
v
2
The mass is
m
=
25
k
g
The velocity is v
=
10
m
s
−
1
So,
K
E
=
1
/2
x25
x
10
2^2=
1250
J
pls mark brainiest answer
Answer:
156.96 N
Explanation:
F=ma where m is the mass and a is acceleration
Substituting 16 Kg for m and 9.81 m/s2 for g then
F=16*9.81= 156.96 N
Answer:
Part a)
When spring compressed by 2 cm
H = 1.47 m
Part b)
When spring is compressed by 4 cm
H = 5.94 m
Explanation:
Part a)
As we know that the spring is compressed and released
so here spring potential energy is converted into gravitational potential energy at its maximum height
So we will have
so we have
Part b)
Similarly when spring is compressed by 4 cm
then we have
so we have
